6x + 12x + 2x = 80 20x = 80 x = 4
Subtracting gives: 10x = 80 so x = 8 and y = 5
x=8 12x-16=80 add 16 to both sides of the equation 12x=96 divide both sides of equation by 12 x=8
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
94+94+80+80=348.
80 + 8 = 88
80 + 50 = 130
80 80 + —— 160 160 80 + —— 240
Let l = x for the sake of clarity: 4x +39 = 14x -41 4x -14x = -41 -39 -10x = -80 x = 8 So: l = 8
Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
200