Subtracting gives: 10x = 80 so x = 8 and y = 5
x=8 12x-16=80 add 16 to both sides of the equation 12x=96 divide both sides of equation by 12 x=8
94+94+80+80=348.
80 80 + ββ 160 160 80 + ββ 240
4x +13 = 93-6x. Adding 6x to each side gives: 10x+13 = 93. Subtracting 13 from each side gives: 10x = 80. Dividing both sides by 10 gives: x = 8.
6x + 12x + 2x = 80 20x = 80 x = 4
Subtracting gives: 10x = 80 so x = 8 and y = 5
x=8 12x-16=80 add 16 to both sides of the equation 12x=96 divide both sides of equation by 12 x=8
24
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
94+94+80+80=348.
Let l = x for the sake of clarity: 4x +39 = 14x -41 4x -14x = -41 -39 -10x = -80 x = 8 So: l = 8
80 80 + ββ 160 160 80 + ββ 240
4x +13 = 93-6x. Adding 6x to each side gives: 10x+13 = 93. Subtracting 13 from each side gives: 10x = 80. Dividing both sides by 10 gives: x = 8.
80 + 50 = 130
80 + 8 = 88
The answer is 560. Simply add the numbers together like you would for two plus two. To check your work, a calculator is the best option.