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Subtracting gives: 10x = 80 so x = 8 and y = 5

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Q: 4x plus 6y equals 62 -6x plus 6y equals -18?
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4x plus 6y equals 62 and -6x plus 6y equals -18?

4x+6y=62 -6x+6y=-18 what is the ordered pair


What is the variable in 18-4x equals 62?

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What is the ordered pair of 4x plus 6y equals 62 -6x plus 6y equals -18?

4x + 6y = 62-6x + 6y = -18 Multiply this equation by -1 the result will be_______________4x + 6y = 626x - 6y = 18_______________ Equation 1 + Equation 2 the result will be10x = 80 ----> X=8Put the value of X in one of the Equations above to find the value of yand so Y=5


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If ab equals 4x plus 8 bc equals 8x plus 4 and ac equals 18x minus 11 what are the following values x ab bc and ac?

Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11