4x+6y=62 -6x+6y=-18 what is the ordered pair
4x + 6y = 62-6x + 6y = -18 Multiply this equation by -1 the result will be_______________4x + 6y = 626x - 6y = 18_______________ Equation 1 + Equation 2 the result will be10x = 80 ----> X=8Put the value of X in one of the Equations above to find the value of yand so Y=5
62
1,162
31.28 - 1.07 + 62 = -31.79
4x+6y=62 -6x+6y=-18 what is the ordered pair
x=11
4x + 6y = 62-6x + 6y = -18 Multiply this equation by -1 the result will be_______________4x + 6y = 626x - 6y = 18_______________ Equation 1 + Equation 2 the result will be10x = 80 ----> X=8Put the value of X in one of the Equations above to find the value of yand so Y=5
13
62
62
(9,2)
62
1,162
31.28 - 1.07 + 62 = -31.79
62
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11