Definitely not. A plane in only two dimensional and if the point P does not necessarily have to be in those two dimenions. It can be but does not have to be.
Infinite planes can be drawn through point A that lies outside plane P. Each plane can be oriented differently, intersecting plane P at various angles, or not intersecting it at all. The only constraint is that the planes must pass through point A, allowing for countless possibilities in their orientation.
It is possible.
False. In order for the line PQ to lie in plane B, then both P and Q must lie in plane B.
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Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).
Hilda P. Hudson has written: 'Cremona transformations in plane and space'
apex it’s true on god
It's x = 0. Consider a point of the plane, P=(x, y), in cartesian coordinates. If P is a point belonging to x-axis, then P=(x, y=0); if P is a point belonging to y-axis, then P=(x=0, y).
Yes, since a plane is a two dimensional surface that extends to infinity in both directions
A Cartesian plane is a 2-dimensional, flat surface. The plane has two mutually axes that meet, at right angles, at a point which is called the origin. Conventionally the axes are horizontal (x-axis) and vertical (y-axis) and distances from the origin are marked along these axes. The position of any point in the plane can be uniquely identified by an ordered pair, (p, q) where p is the distance of the point along the x-axis (the abscissa) and q is the distance of the point along the y-axis (the ordinate).
The image of point P(2, 3, 5) after a reflection about the xy-plane is P'(2, 3, -5). This means that the x and y coordinates remain the same, but the z coordinate is negated.
ab is a straight line in the plane p.