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If Sally can paint a house in 4 hours and John can paint the same house in 6 hour how long will it take for of them to paint the house together?
Wiki User
∙ 13y ago
Sally does a quarter of the house in an hour, John does one-sixth, so together they
would do 5/12 in an hour, thus it would take 12/5 hours ie 2 hrs 24 min in theory.
In practice, because of arguments it would probably take three hours plus!
Wiki User
∙ 13y ago
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What formula is used to determine If sally cfan paint a house in four hours and john can paint the same house in 6 hours how long will it take for both of them to paint the house together?
You don't need a formula. You need to understand where the answer comes from. If you understand where the answer comes from, you can write your own formula. If you don't, then a formula can be dangerous in your hands. -- Sally can paint 1/4 of the house in an hour. -- John can paint 1/6 of the same house in an hour. -- If they work together, then can paint (1/4 + 1/6) = 5/12 of the house in an hour. -- If they paint 5/12 of the house in an hour, then it takes them 12/5 hours to finish the job, or 2.4 hours, or 2hours 24minutes. Well, OK. Here's the formula: S = number of hours it takes Sally J = number of hours it takes John Number of hours it takes them working together = 1 / (1/S + 1/J)
If sally can paint a house in four hours and john can paint the same house in 6 hours how long will it take for both of them to paint the house together?
Sally does 1 job in 4 hours ===> 1/4th of the job per hour.John does 1 job in 6 hours ===> 1/6th of the job per hour.Working together, they do (1/4 + 1/6) = (3/12 + 2/12) = 5/12 job per hour.The job takes 12/5 = 2.4 hours = 2hours24minutes to complete.
It takes Sal 5 hours to paint a house It takes Sal 3 hours to paint the same house How long will it take to paint the house if both of them work together?
It would take them 4 hours to paint the house together.
If sally paints a house 4 hrs and john paints the same house in 6 hrs how long will it take to paint the house together?
144 minutes.
Caroline can paint a fence in 6 hours Her sister Lily can paint the same fences in 4 hours How long will it take them to paint the fence if they work together?
Caroline can paint half the fence in 3 hours and Lily can paint half the fence in 2 hours, so it will take a total of 5 hours for them to paint the fence while working together.
How do you translate a word phrase into a math expression?
if sally can paint a house in 4 hours and john can paint the same house in 6 hours, how long will it take for them to paint the house together?
If sally can paint a house in four hours and john can paint the same house in 6 hours how long will it take both of them to paint the house?
In one hour Sally paints one quarter and John paints one sixth, between them they paint five twelfths per hour so would take 2 hours 24 minutes if they worked together. But have you ever known a male and a female to work harmoniously together? Allow at least three hours!
If Sally can paint a house in 4 hours and John can paint the same house in 6 hour?
2 Hours & 24 minutes
What formula is used to determine If sally cfan paint a house in four hours and john can paint the same house in 6 hours how long will it take for both of them to paint the house together?
You don't need a formula. You need to understand where the answer comes from. If you understand where the answer comes from, you can write your own formula. If you don't, then a formula can be dangerous in your hands. -- Sally can paint 1/4 of the house in an hour. -- John can paint 1/6 of the same house in an hour. -- If they work together, then can paint (1/4 + 1/6) = 5/12 of the house in an hour. -- If they paint 5/12 of the house in an hour, then it takes them 12/5 hours to finish the job, or 2.4 hours, or 2hours 24minutes. Well, OK. Here's the formula: S = number of hours it takes Sally J = number of hours it takes John Number of hours it takes them working together = 1 / (1/S + 1/J)
It takes Sal 5 hours to paint a house It takes Sal 3 hours to paint the same house How long will it take to paint the house if both of them work together?
It would take them 4 hours to paint the house together.
If sally can paint a house in four hours and john can paint the same house in 6 hours how long will it take for both of them to paint the house together?
Sally does 1 job in 4 hours ===> 1/4th of the job per hour.John does 1 job in 6 hours ===> 1/6th of the job per hour.Working together, they do (1/4 + 1/6) = (3/12 + 2/12) = 5/12 job per hour.The job takes 12/5 = 2.4 hours = 2hours24minutes to complete.
If john can paint a house in 5 hours and joe can paint a house in 3 hours how long will it take for both of them to paint the house?
The way you calculate this (assuming that both work at constant speed) is:* Calculate what part of the house each person can paint in an hour. * Add both fractions together, to calculate what part of the house you can paint together. * Take the reciprocal of this last result, to calculate the number of hours.
If sally paints a house 4 hrs and john paints the same house in 6 hrs how long will it take to paint the house together?
144 minutes.
If Sarah paints a room in 4 hours and sam paints the same room is 6 hours how long will it take for both to paint one room?
We know that Sally can paint the house by herself in four hours. Put another way, she can paint 1/4 of the house in an hour. Using similar logic, we know John paints at a rate of just 1/6 of a house per hour. If we convert those fractions to fractions with a common denominator, we have 3/12 of a house for Sally and 2/12 of a house for John, so together they can paint at a rate of 5/12 of a house per hour. But that is not yet the answer to the question. If you take the reciprocal of 5/12 houses per hour, you get 12/5 hours per house. That equals 2.4 hours per house. Converting to hours and minutes, you get 2 hours, 24 minutes -- because 0.4 hours equals 24 minutes. (0.4 hours x 60 minutes/hour = 24 minutes.) Algebra OR Above answer of this question is right.but we can also define it some other way, in percentage. May be this solution make esay for some friends to understand.Silly tooks 4 hors to paint 100 % (full house).Jhon tooks 6 hours to paint 100 % (Full house).In an hoursilly can paint 25 % of house & Jhon can paint 16.66 % of house, so they both can paint 41.66 percent of house in an hour.so, if we divide (total required work) / (work they can do in an Hour)= 100 / 41.66we I'll get the total time to paint complete house.ANSWERS IS : 2.4 Hours or 2 hours 24 minutes.
If Joe can paint a house in 3 hours and Sam can paint the same house in 5 hours how long does it take for them to do it together?
Joe can paint the house in 3 hours so Joe paints 1/3 house in an hour. Similarly, Sam paint 1/5 of the house in one hour. So together (assuming no synergy) they paint 1/3 + 1/5 = 8/15 of the house in an hour. So they take 15/8 = 1 + 7/8 = 1.875 days to paint it.
Caroline can paint a fence in 6 hours Her sister Lily can paint the same fences in 4 hours How long will it take them to paint the fence if they work together?
Caroline can paint half the fence in 3 hours and Lily can paint half the fence in 2 hours, so it will take a total of 5 hours for them to paint the fence while working together.
If Jill paints the house in 5 hours and tom paints the house in 4 how long will it take them to paint the house together?
distance=rate*time Jill can paint 1 house in 5 hours. 1=r*5 r=1/5 houses/hour Tom can paint 1 house in 4 hours. 1=r*4 r=1/4 houses/hour 1 house = 1/5*x+1/4*x 1=(4x+5x)/20 20=9x x= 2.2 repeating hours (2 hours, 13 minutes, 20 seconds)
