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If a bag contains three red and three blue marbles and if three marbles are chosen without replacement what is the probability that they will be all red or all blue?
Wiki User
∙ 14y ago
There are 6!/3! = 120 possible combinations of marble colour. Of these, only 2 are "good". This gives a probability of 2/120 = 1/60 = 0.0167, or about one and two-thirds of a percent.
Wiki User
∙ 14y ago
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In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
In a bag there are 3 red marbles and B blue marbles. Two marbles are randomly selected from the bag without replacement. The probability that the two marbles are the same color is 0.5. What is the sum?
7
You have 12 marbles 8 are blue 4 are green what is probability one of each color is chosen on the first two draws?
If the two marbles are drawn without replacement, the probability is 16/33.
What is the probability of pulling a red marbles out of a bag containing 16 red marbles 10 green marbles 14 blue marbles and 10 yellow marbles?
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?
4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.
A container holds 6 red marbles and 4 green marbles You select 2 marbles from each container without replacement What is the probability that you will select 1 red marble and 1 green marble?
sure chance
A bag contains 5 green marbles 3 yellow and 2 red marbles. What is the probability of picking three green marbles from the bag without replacement?
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D
A bag contains 3 blue marbles and 4 red marbles. What is the probability that three randomly drawn marbles without replacement will all be red?
The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.
A box contains 3 white 5 red 2 green and 4 blue marbles two marbles are drawn without replacement what is the probibality of drawing two red marbles?
I believe it would be 5 red marbles of 14 total marbles (5/14)
What does without replacement mean in probability?
Im not good at explaining things but here's an example. If I have 5 red marbles and 6 blue marbles in a bag and I pick one out. I then choose another marble without returning the first marble to the bag. Hope this helps.
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What is the probability of 6 green marbles?
We can't answer that without knowing what else is in the bowl.
A jar contains three colored marbles 10 red 15 green and 25 blue If you were to choose without looking what is the probability of selecting a blue marble?
25/50 gives the probability of selecting a blue marble
