answersLogoWhite

0

What else can I help you with?

Related Questions

If a box contains 4 red marbles seven white and 5 blue and two marbles are drawn one at a time with replacement What is the probability that both marbles are white?

Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.


A box contains 3 red marbles 6 blue marbles 12 green marbles and 4 purple marbles if a marble is drawn from the box what is the probability that it is red?

There are a total of 25 Marbles The chances are 3 out of 25 drawing a Red marble. 3/25 = 12% chance of drawing a red marble


A jar contains 8 red marbles 9 blue marbles and 6 green marbles Two marbles are picked at random What is the probability that one is green and one is blue?

Without replacement: P(one green and one blue) = P(drawing green then blue) + P(drawing blue then green) = (6/23)(9/22) + (9/23)(6/22) = 104/506 = 52/253 With replacement: P(one green and one blue) = P(green)*P(blue) = (6/23)(9/23) = 54/529


A bag contains 10 black marbles and 10 white marbles Five marbles are drawn and then replaced each time What is the probability of drawing five white marbles in a row?

It is (1/2)5 = 1/32


A bag contains 3 white marbles 7 green marbles and 5 yellow marbles What is the probability of drawing a yellow marble?

5/15 = 1/3 = 33 and 1/3 percent


A box contains 8 green marbles 4 red marbles and 4 purple marbles if you draw a marble at random what is the probability that you will not draw a red marble?

Probability of drawing a red marble = 4/16 = 1/4 Probability of drawing not a red marble = 1 - 1/4 = 3/4


What is the theoretical probability of randomly drawing a green marble if there are 5 red marbles 8 blue marbles and 12 green marbles in a bag.?

The theoretical probability of randomly drawing a green marble can be calculated by dividing the number of green marbles by the total number of marbles in the bag. In this case, there are 12 green marbles out of a total of 5 red marbles + 8 blue marbles + 12 green marbles, which is 25 marbles in total. Therefore, the theoretical probability of drawing a green marble is 12/25 or 48%.


A bag contains 6 red marbles 7 blue marbles and 6 green marbles If one marble is randomly picked from the bag what is the probability that this is a blue marble?

There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.


If you have a bag of 4 red and 4 green marbles what is the probability of drawing 2 marbles without replacement and getting 2 green marbles?

4/8 or 1/2(probability of first draw) * 3/8(probability of second draw which is 12/64 or 3/16 of the given scenario.


How many marbles 7 bags if each bag contains 8 marbles?

56 marbles


A bag contains 2 yellow 12 red and 6 green marbles What is the probability of selecting a red marble replacing it then selecting another red marble?

The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25


How many are there in 700 bags if each bag contains 8 marbles?

700 bags if each bag contains 8 marbles is a total of 5600 marbles.