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assume river velocity = X mph boat velocity = 20 mph

time to go 6 miles downstream = T1

time to go 3 miles upstream = T2

distance = time * velocity

downstream: 6 mi = T1 * (boat velocity + river velocity)

upstream: 3 mi = T2 * (boat velocity - river velocity)

6 = T1 * ( 20 + X )

3 = T2 * ( 20 - X )

T1 * ( 20 + X ) = 2 * ( T2 * ( 20 - X ) )

since T1 = T2 then

20 + X = 40 - 2X

3X = 20

X = 6.67

thus, river velocity is 6.67mph

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Q: If a boat can go 20 miles per hours in still water and can go six miles downstream and 3 miles up stream in the same time how fast is the river?
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