A1 If you simplify the image of a cell to that of a sphere, then you can use the equations for working out the volume or surface area as reference. The volume of a sphere = (4/3)*pi*(r^3), that is four thirds of pi multiplied by the radius of the sphere cubed. The surface area of a sphere = 4*pi*(r^2), that is four pi multiplied by the radius of the sphere squared. You can equate these to each other to find the relationship of volume to surface area. Deriving this, you get the equation that (Surface Area^2) = 24*pi*Volume. That is, as the area increases, the volume increases at an exponential rate. So, in answer to your question, the volume increases more quickly than the surface area. A2 Something odd about lines 7-9 above. You can't equate the volume to the area. What you can say is that V = A x r/3, so the conclusion is right. What you should really do is use differential calculus: V = 4/3 x pi x r3, therefore dV/dr = 12/3 x pi x r2. A = 4 x pi x r2, therefore dA/dr = 8 x pi x r.
So the rate of increase of A is proportional to r, whilst that of V is proportional to r2
The ratio increases. Farting does not occur
false, the volume becomes faster......
p.s. I have the same homework sheet
Its called the square-cubed law.
double the size and the surface is 4 times as big while the volume is 8 times as big.
True.
No
Although they do not increase at the same rate, as the surface area increases the volume increases slowly.
It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
If a cell gets too large the function of the cell will decrease. This is because of the surface area to volume ratio, when the volume increase the surface area increases at a slower rate so it is harder for things to pass through the cell, and not as much room for things to enter and exit the cell.
if volume of a gas increases temperature also increases
The cerebrum has many folds or wrinkles which increases the surface without increasing the volume
The volume increases faster. (proportional to the cube of the radius)The surface area increases slower. (proportional to the square of the radius)
Although they do not increase at the same rate, as the surface area increases the volume increases slowly.
If you increase the radius, the volume will increase more than the area.
It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
They both increase. The rate of increase of the surface area is equivalent to the rate of increase of the volume raised to the power 2/3.
increases: by approximately the square of the cube root of the volume increase (that would be exact if the cell was a sphere). Or, in other words, if you double the size (diameter) of a cell. its surface area increases by a factor of 4, and it volume increases by a factor of 8.
It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.
If a cell gets too large the function of the cell will decrease. This is because of the surface area to volume ratio, when the volume increase the surface area increases at a slower rate so it is harder for things to pass through the cell, and not as much room for things to enter and exit the cell.
if volume of a gas increases temperature also increases
If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .The ratio of surface area to volume is 6S2/S3 = 6/S .This number is inversely proportional to 'S'. So as the side increases ...causing the volume to increase ... the ratio does decrease, yes.