oh dear If a cell's surface area is 6 SQUARE cms and its VOLUME is 1cm cubed then the ratio of surface area to volume is 6:1
6:1
Surface area to volume ratio
When cells get smaller, the volume (as well as mass) decreases faster than the surface area so the surface:volume increases. Cells with a high surface:volume are more effective in receiving nutrients through diffusion. A cell (assume perfect sphere) with radius 2 has a surface area of 16pi and volume of 32pi/3. A cell with radius 3 has a surface area of 36pi and volume of 108pi/3. Also relatively speaking, volume can be thought of as y=x3 and surface area as y=x2. When there is a change in x, the change is more dramatic in the volume, so small cells have high ratios and large cells have low ratios.
surface area/ volume. wider range of surface area to volume is better for cells.
3 to 7
surface area/ volume. wider range of surface area to volume is better for cells.
As cell volume increases, the ratio of cell surface area to cell volume decreases. This is because the surface area increases by a square factor while the volume increases by a cube factor. A higher surface area to volume ratio is more favorable for efficient nutrient exchange and waste removal in cells.
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
533 m2/1,372 m3 = 0.3885 per meter (rounded)
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
It increases.
It would help to know why what!