Q: If a equals b and b equals c and c equals d and and d equals e then what does e equal?

Write your answer...

the answer is a

a = b changes the value of a and makes it the same as the value of b. a == b does not change the values of a or b. It is an expression that is equal to 1 if a and b are the same or to 0 if a and b are different. For example: if ( a == b) { c = d;} means if a and b are the same, then set c equal to d. C does let you write the following: if ( a = b) { c = d;} This sets a equal to the value of b, and then if the new value of a is non-zero, it sets c equal to d. You can do this, but if you see a single equal sign in an "if" condition, that usually (but not always) is a mistake.

If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."

As A/B=C/D , So B=(A*D)/C

Fractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*CFractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*CFractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*CFractions A/B and C/D are equivalent if the cross-multiples are equal. That is, is A*D = B*C

z remains undefined.

if a/b=c/d then a+b/c+d = a/b=c/d

If: a = b+c+d Then: c = a-b-d

If a, b, c and d are all non-zero then ab = CD if and only if a/c = d/b or (equivalently) a/d = b/c

657

A statement that two ratios are equal; such as A over B equals C over D

The product of the means equals the product of the extremes. In other words, if A is to B as C is to D, then B times C equals A times D, so... A = B x C Ã· D B = A x D Ã· C C = A x D Ã· B D = B x C Ã· A

The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a

And how does this relate to coins?

a + b = c a - b = d then a = (c + d)/2 and b = (c - d)/2 The fact that c and d are perfect squares is not relevant to solving a and b in terms of c and d. Furthermore, a complete solution of all four variables into unique numerical values is not possible.

The ratios a/b and c/d [ or a:b and c:d ] are equal if (and only if) a*d = b*c

Two intervals (a, b) and (c, d) are said to be equal if b - a = d - c.

If bd ≠ 0, then a/b + c/d (the common denominator is bd) = (a x d)/(b x d) + (c x b)/(d x b) = ad/bd + cb/db = ad/bd + cb/bd = (ad + cb)/ bd

If a is to b as c is to d, a x d = b x c. The product of the means (b & c) equals the product of the extremes (a & d).

Multiply the antecedent of each ratio by the consequent of the other. If the products are equal, the ratios are equivalent.For example, given the two ratios A:B and C:D, if the product of A and D equals the product of B and C, then A:B::C:D (A is to B as C is to D).Two ratios a:b and c:d are equivalent if the crossproducts are the same.That is a/b = c/d if and only if a*d = b*c.

Yes. To show the conditions on a, b, c and d given that if a/b = c/d then a+b = c+d. Suppose b != d (and that both b and d are non-zero) then: d = kb for some number k (!= 0), so c/d = c/kb = (c/k)/b so a/b = (c/k)/b => a = c/k => c = ka Thus: c + d = ka + kb = k(a + b) Which means that c + d = a + b only if k = 1. Thus if a/b = c/d then a + b = c + d only if a = c and b = d. The condition on b and d both being non-zero prevents the possibility of division by zero. If either is zero, a division by zero will occur and at least one of the fractions is infinite.

A plus b plus c equals d. A is the largest answer b is the smallest answer and d is less than 6?''

c

With no knowledge about A, B, C and D or the relation between them, it is impossible to give an answer.