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If a equals b and b equals c and c equals d and and d equals e then what does e equal?
They all equal each other. a = b = c = d = e e = a e = b e = c e = d e = e
If a plus b equals c and b plus c equals d and c plus d equals e and a equals 7 and e equals 5 what is a plus b plus c plus d plus e equal?
the answer is a
How do you solve a equals b plus c plus d solve for c?
If: a = b+c+d Then: c = a-b-d
What is a proprtion?
A statement that two ratios are equal; such as A over B equals C over D
If bd does not equal 0 then a over b plus c over d equals?
If bd ≠ 0, then a/b + c/d (the common denominator is bd) = (a x d)/(b x d) + (c x b)/(d x b) = ad/bd + cb/db = ad/bd + cb/bd = (ad + cb)/ bd
How is a plus b over a minus b equals c plus d over c minus d?
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
If a equals b and b equals c and c equals d and and d equals e then what does e equal?
They all equal each other. a = b = c = d = e e = a e = b e = c e = d e = e
Maria keeps her four stuffed bears lined up on a shelf over her bed how many arrangements of the bears are possible?
The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a
If a plus b equals c and b plus c equals d and c plus d equals e and a equals 7 and e equals 5 what is a plus b plus c plus d plus e equal?
the answer is a
If a over b equals c over d then is it possible that a plus b equals c plus d and why?
Yes. To show the conditions on a, b, c and d given that if a/b = c/d then a+b = c+d. Suppose b != d (and that both b and d are non-zero) then: d = kb for some number k (!= 0), so c/d = c/kb = (c/k)/b so a/b = (c/k)/b => a = c/k => c = ka Thus: c + d = ka + kb = k(a + b) Which means that c + d = a + b only if k = 1. Thus if a/b = c/d then a + b = c + d only if a = c and b = d. The condition on b and d both being non-zero prevents the possibility of division by zero. If either is zero, a division by zero will occur and at least one of the fractions is infinite.
How do you solve a equals b plus c plus d solve for c?
If: a = b+c+d Then: c = a-b-d
What is a proprtion?
A statement that two ratios are equal; such as A over B equals C over D
Would you Prove If a equals b and c d then a plus c b plus d?
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
How do you work a proportional problem?
The product of the means equals the product of the extremes. In other words, if A is to B as C is to D, then B times C equals A times D, so... A = B x C ÷ D B = A x D ÷ C C = A x D ÷ B D = B x C ÷ A
What can you use to rewrite a over b equals c over d as ad equals cb?
it is the crossproducts property...right that down now...
If bd does not equal 0 then a over b plus c over d equals?
If bd ≠ 0, then a/b + c/d (the common denominator is bd) = (a x d)/(b x d) + (c x b)/(d x b) = ad/bd + cb/db = ad/bd + cb/bd = (ad + cb)/ bd
Can somebody solve the equations a plus b equals c and a-b equals d where a b c and d are perfect square integers?
a + b = c a - b = d then a = (c + d)/2 and b = (c - d)/2 The fact that c and d are perfect squares is not relevant to solving a and b in terms of c and d. Furthermore, a complete solution of all four variables into unique numerical values is not possible.
