Make 'b' a negative number with a higher absolute value than 'a' - for example, a = 4 and b = -5. Then b2 will always be greater than a2.
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2
To factor a perfect square, it should be in the form a2+2ab+b2 For example: 9x2+18xy+9y2 First factor out the 9: 9(x2+2xy+y2) Make a2+2ab+b2 into (a+b)2 : 9(x+y)2
(a3 + b3) = (a + b)(a2 - ab + b2)
a3+ b3 = (a + b)(a2 - ab + b2)
y2 - 64 can be written as y2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, y2 - 64 is factored as (y+8)(y-8).
One way to prove this is as follows: Given a > b and a>0 and b>0 Define a new constant 'n' such that a - b = n then a2 = (b + n)2 a2 = b2 + 2bn + n2 since b and n are both positive, 2bn is a positive value and n2 is also positive So a2 > b2 because a2 - 2bn - n2 = b2
Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )Assuming the sale is in B2 and the cost in A2, you could use the following formula to do it:=IF( B2>=A2*1.25, B2*7%, 0 )
They are: a2+b2 = c2 c2-a2 = b2 c2-b2 = a2
call the numbers a & b (a+b)2 = a2+2ab+b2 which is greater than a2 + b2 by twice the product of the numbers. Check: say 3 and 5 32 + 52 = 9 + 25 = 34 (3 +5)2 = 64, greater by twice a x b. QED -------------------- If a and b are the numbers, then (a+b)2 = a2 + 2ab + b2, which is different from a2 + b2 (not necessarily larger). The two quantities are equal only when one (or both) of a,b is zero.
a2+2a2b+2ab2+b2
v2 = b2 (a2 - x2)Divide each side by b2 :v2/b2 = a2 - x2Subtract a2 from each side:v2/b2 - a2 = -x2Multiply each side by -1 :x2 = a2 - v2/b2Take the square root of each side:x = ± sqrt ( a2 - v2/b2 )
a2-b2 = (a-b)(a+b)
If you are talking about a2+b2=c2 then that is Pythagorean theorem.
Your formula is not complete as you do not say what happens if the A cell contains 1 and is therefore not bland and not over 1. Using cells A2 and B2 the formula would be put into cell B2 and would be: =IF(A2="","",IF(A2>1,"Hours",""))
a2
C2=A2+B2 Therefore to find B2: B2=C2-A2
The Pythagorean theorem is a2 + b2 = c2