call the numbers a & b
(a+b)2 = a2+2ab+b2
which is greater than a2 + b2 by twice the product of the numbers.
Check: say 3 and 5
32 + 52 = 9 + 25 = 34
(3 +5)2 = 64, greater by twice a x b. QED
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If a and b are the numbers, then (a+b)2 = a2 + 2ab + b2, which is different from a2 + b2 (not necessarily larger). The two quantities are equal only when one (or both) of a,b is zero.
5
sum of squares: 32 + 52 = 9 + 25 = 34 square of sum (3 + 5)2 = 82 = 64 This is a version of the Cauchy-Schwarz inequality.
3 and 5
x2 + y2 = (x + y)2 => x2 + y2 = x2 + 2xy + y2 => 2xy = 0 => xy = 0 So, one of x and y must be 0.
The numbers are 12 and 14.
split 10 in two parts such that sum of their squares is 52. answer in full formula
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
Sum of squares? Product?
Not unless at least one of the numbers is zero.
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
For an array of numbers, it is the square of the sums divided by the sum of the squares.
It squares numbers and add the totals together. The square of 2 is 4, the square of 5 is 25. The sum of squares of 2 and 5 is therefore 29. That would done in the SUMSQ function like this: =SUMSQ(2,5)
Oh, what a lovely question! To compute the sum of the squares of N numbers, you can create a simple algorithm. Start by initializing a variable to hold the sum, then loop through each number, square it, and add it to the sum. Once you've done this for all N numbers, you'll have the sum of their squares. Just like painting a happy little tree, take your time and enjoy the process.
It is not clear what the question means: there are 31 2-digit numbers that can be expressed as a sum of two squares.
The sum of their squares is 10.
Square the numbers and then add them together. Example: 62 + 82 = 36 + 64 = 100
The one in which the square of the biggest one is equal to the sum of the squares of the other two is.