c2=a2+b2
102=62+b2
100=36 + b2
b2=64
b=8
27
Regard the ladder as the hypotenuse and the distance from the wall as one leg of a right angled triangle. Then, 262 = 102 + H2 : where H is the height reached up the wall by the ladder. H2 = 676 - 100 = 576 : H = √576 = 24
It depends on the size of the bricks and their orientation.
15
10 ft = 3.048 metres.
he should bud the ladder so it wouldn't be able to reach
27
15 meters, or less, depending on the angle.
18
that depends on the hieght of the building.
23.53
The diagonal is 14.142 feet.
Answer your self dont know
Regard the ladder as the hypotenuse and the distance from the wall as one leg of a right angled triangle. Then, 262 = 102 + H2 : where H is the height reached up the wall by the ladder. H2 = 676 - 100 = 576 : H = √576 = 24
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
Twenty divided by the cosine of 32 gives you 23.584 ft
17