Q: If a number has a 9 in the ones place is it always divisible by 3?

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No; for a number to be divisible by 10, the last number (ones place) must be zero.

To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.

Because such a number is divisible by ten, and five is a factor of ten. Hence, such a number is also divisible by five.

2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.

Yes

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No; for a number to be divisible by 10, the last number (ones place) must be zero.

To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.

Because such a number is divisible by ten, and five is a factor of ten. Hence, such a number is also divisible by five.

2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.

Yes

The number immediately to the left of the ones place is the tens place or the 101 place. Since the value of any digit, d, there would be d*101 = d*10, it will be divisible by 10. The next number to the left is the hundreds place or the 102 place. Since the value of any digit, d, there would be d*102 = d*100, it will be divisible by 10. All the numbers further to the left have place values that are higher integer powers of 10 and so whatever the digit in that place, they will be divisible by 10. And so the answer follows.

Any number that has a 5 or 0 in the ones place is divisible by 5. If a number is evenly divisible by another number, it is NOT prime.

No, a trick you can use is that the ones place in the number has to either be a 5 or a 0 in order for it to be divisible by 5.

its evenly divisible by 5 with no remainder

185 is composite because anything that has 5 in the ones place is always divisible by 5. A prime number is a number that can only divided equally by itself and 1, so since 185 is divisible by 185, 1, 5, and 37, it is not a prime number.

16 is even because it is divisible by 2 and has a 6 in the ones place.

The possibilities for a digit in the ones place of a prime number greater than 5 are 1, 3, 7, and 9. If a 0, 2, 4, 6, or 8 is in the ones place, the number is divisible by 2, so it would not be prime. If a 5 is in the ones place, the number is divisible by 5, so it would not be prime.