Yes
The possibilities for a digit in the ones place of a prime number greater than 5 are 1, 3, 7, and 9. If a 0, 2, 4, 6, or 8 is in the ones place, the number is divisible by 2, so it would not be prime. If a 5 is in the ones place, the number is divisible by 5, so it would not be prime.
No, just numbers that have a 0 in their ones place
Are you asking what the divisibility rule for 4 is?===========A number is divisible by 5 if it ends in a 0 or a 5=====There are two ways to test for divisibility by 4.A number is divisible by 4 if it is divisible by 2 twice. That is, the factor you get when you factor a 2 out must also be divisible by 2.Example... is 516 divisible by 4?Well, is it divisible by 2? Yes, it is even. Factor that 2 out you get 258. Is 258 also divisible by 2? Yes, it too is even. Since it was divisible by 2 and the quotient was also divisible by 2 then the original was divisible by 4.But, 4's have another rule that is simpler.All you have to do is look at the smallest two digits: the ones and tens place. You can ignore anything in the hundreds place or up. If the ones and tens place form a number that is divisible by 4 then the whole number is also divisible by 4Example: Is 52848474116 divisible by 4?Just take the last two digits off and test them. 16. Is 16 divisible by 4? Yes, so that whole mess of a number is also.
It is true (as long as there are no decimal places after the ones place) because those numbers will always be divisible by 2, 5, and 10. With exception of the number zero which is neither prime nor composite.
102 is divisible by: 1 2 3 6 17 34 51 102.
The number immediately to the left of the ones place is the tens place or the 101 place. Since the value of any digit, d, there would be d*101 = d*10, it will be divisible by 10. The next number to the left is the hundreds place or the 102 place. Since the value of any digit, d, there would be d*102 = d*100, it will be divisible by 10. All the numbers further to the left have place values that are higher integer powers of 10 and so whatever the digit in that place, they will be divisible by 10. And so the answer follows.
The possibilities for a digit in the ones place of a prime number greater than 5 are 1, 3, 7, and 9. If a 0, 2, 4, 6, or 8 is in the ones place, the number is divisible by 2, so it would not be prime. If a 5 is in the ones place, the number is divisible by 5, so it would not be prime.
No, just numbers that have a 0 in their ones place
No, all numbers with a zero in the one's place are divisible by at least 1, themselves, and 2, which means they cannot be prime.
Aside from 5 itself, all numbers ending with the digit 5 are divisible by 5, and therefore composite.
Are you asking what the divisibility rule for 4 is?===========A number is divisible by 5 if it ends in a 0 or a 5=====There are two ways to test for divisibility by 4.A number is divisible by 4 if it is divisible by 2 twice. That is, the factor you get when you factor a 2 out must also be divisible by 2.Example... is 516 divisible by 4?Well, is it divisible by 2? Yes, it is even. Factor that 2 out you get 258. Is 258 also divisible by 2? Yes, it too is even. Since it was divisible by 2 and the quotient was also divisible by 2 then the original was divisible by 4.But, 4's have another rule that is simpler.All you have to do is look at the smallest two digits: the ones and tens place. You can ignore anything in the hundreds place or up. If the ones and tens place form a number that is divisible by 4 then the whole number is also divisible by 4Example: Is 52848474116 divisible by 4?Just take the last two digits off and test them. 16. Is 16 divisible by 4? Yes, so that whole mess of a number is also.
Since there are an infinite number of these, you cannot list them, but here's how you tell: Any non-zero integer which has one of the following in the ones place (rightmost digit): either a 5 or a 0
It is true (as long as there are no decimal places after the ones place) because those numbers will always be divisible by 2, 5, and 10. With exception of the number zero which is neither prime nor composite.
A can be 0 or 9.
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
102 is divisible by: 1 2 3 6 17 34 51 102.
All numbers are divisible by 1. So, apart from the number 1, all numbers are divisible by another number. These numbers are therefore prime or composite.