The number immediately to the left of the ones place is the tens place or the 101 place. Since the value of any digit, d, there would be d*101 = d*10, it will be divisible by 10.
The next number to the left is the hundreds place or the 102 place. Since the value of any digit, d, there would be d*102 = d*100, it will be divisible by 10.
All the numbers further to the left have place values that are higher integer powers of 10 and so whatever the digit in that place, they will be divisible by 10.
And so the answer follows.
Yes, 268 is divisible by 2 and 4. To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2. To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits
Yes because the number in the one's place is a 0.
No, a number can only be divisible by a number smaller than it
No. 15, 25, 35, and 1675 are divisible by 5, but not by 10. However, every number divisible by 10 is also divisible by 5.
712 is divisible by 2 because the digit at ones place is an even number. 712 is not divisible by 3 because the sum of the numbers(7+1+2=10) is not divisible by 3. 712 is divisible by 4 as the last two digits(12) are divisible by 4. 712 is not divisible by 5 because the last digit is neither 5 nor 0. 712 is not divisible by 6 because it is not divisible by 3. 712 is not divisible by 10 because the last digit is not 0.
No; for a number to be divisible by 10, the last number (ones place) must be zero.
Yes
No, just numbers that have a 0 in their ones place
No. In order for a number to be divisible by 10, the ones digit must be zero (0).
Yes, 268 is divisible by 2 and 4. To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2. To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits
If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.
Yes because the number in the one's place is a 0.
Every number divisible by 10 is divisible by 5.
If the one's place is a 0, then it is divisible by 10.
yes 43,469,386,260 ends in 0 so is exactly divisible by 10 and 5
It is true (as long as there are no decimal places after the ones place) because those numbers will always be divisible by 2, 5, and 10. With exception of the number zero which is neither prime nor composite.
No, a number can only be divisible by a number smaller than it