The number immediately to the left of the ones place is the tens place or the 101 place. Since the value of any digit, d, there would be d*101 = d*10, it will be divisible by 10.
The next number to the left is the hundreds place or the 102 place. Since the value of any digit, d, there would be d*102 = d*100, it will be divisible by 10.
All the numbers further to the left have place values that are higher integer powers of 10 and so whatever the digit in that place, they will be divisible by 10.
And so the answer follows.
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Yes, 268 is divisible by 2 and 4. To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2. To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits
Yes because the number in the one's place is a 0.
No, a number can only be divisible by a number smaller than it
No. 15, 25, 35, and 1675 are divisible by 5, but not by 10. However, every number divisible by 10 is also divisible by 5.
No. Any number that is divisible by 10 is divisible by 5. It doesn't work the other way.