yes
Yes, the result is 795.
Any number which ends in 0 or 5 is divisible by 5. So, obviously 2385 is divisible by 5. This goes for base ten, not base 9 (I think)
1, 3, 5, 9, 15, 45, 53, 159, 265, 477, 795, 2385
Any of its factors
Oh, dude, let me break it down for you. Number 2385 is divisible by 1, 3, 5, 7, 15, 21, 35, 105, 227, 681, 1135, and 2385. So, if you ever need to impress someone at a math party, just drop that knowledge bomb on them. You're welcome.
No. Numbers divisible by 10 end with a zero.
Yes but not evenly, yields a remainder
The numbers that are divisible by 795 are infinite. Some of them are: 795, 1590, 2385, 3180 . . .
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
35 is not divisible by 3.
not without a remainder/decimal. the answer is 589 remainder 2 or 589.5
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.