yes
Any of its factors
No. Numbers divisible by 10 end with a zero.
Any number which ends in 0 or 5 is divisible by 5. So, obviously 2385 is divisible by 5. This goes for base ten, not base 9 (I think)
Yes, the result is 795.
Yes but not evenly, yields a remainder
The numbers that are divisible by 795 are infinite. Some of them are: 795, 1590, 2385, 3180 . . .
not without a remainder/decimal. the answer is 589 remainder 2 or 589.5
Oh, dude, let me break it down for you. Number 2385 is divisible by 1, 3, 5, 7, 15, 21, 35, 105, 227, 681, 1135, and 2385. So, if you ever need to impress someone at a math party, just drop that knowledge bomb on them. You're welcome.
2385
1, 3, 5, 9, 15, 27, 45, 53, 135, 159, 265, 477, 795, 1431, 2385, 7155.
% rate = 2385/42882 * 100%= 0.0556 * 100%= 5.56%