T = 2pi*sqrt(l/g)
Therefore Tm/TE = (2pi*sqrt(l/gm))/(2pi*sqrt(l/gE))
Further simplify: Tm/TE = sqrt(gE/gm)
Tm = sqrt(gE/gm) * TE
Tm = sqrt(9.81 m/s2 / 1.62 m/s2) * 1 s
Tm = 2.46 s
The motion will not be effected. If you build a pendulum in your garage that swings with a period of one second, then bring it on a train, it will again swing with a period of one second, provided the train moves uniformly.
That depends on the period of the clock's pendulum. If we assume it's one second, then it does 1800 cycles in half an hour.
1/4 Hertz or 1.4 per second.
If the length of the second pendulum of the earth is about 1 meter, the length of the second pendulum should be between 0.3 and 0.5 meters.
25m
The motion will not be effected. If you build a pendulum in your garage that swings with a period of one second, then bring it on a train, it will again swing with a period of one second, provided the train moves uniformly.
Second's pendulum is the one which has 2 second as its Time period.
Suppose that a pendulum has a period of 1.5 seconds. How long does it take to make a complete back and forth vibration? Is this 1.5 second period pendulum longer or shorter in length than a 1 second period pendulum?
The time that it "takes" is the period.
The period is 1 second.
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
2 Seconds
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
"Period" has the dimensions of time. Suitable units are the second, the minute, the hour, the fortnight, etc.
That depends on the period of the clock's pendulum. If we assume it's one second, then it does 1800 cycles in half an hour.
1/4 Hertz or 1.4 per second.
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2