The time that it "takes" is the period.
Suppose that a pendulum has a period of 1.5 seconds. How long does it take to make a complete back and forth vibration? Is this 1.5 second period pendulum longer or shorter in length than a 1 second period pendulum?
The physical parameters of a simple pendulum include (1) the length of the pendulum, (2) the mass of the pendulum bob, (3) the angular displacement through which the pendulum swings, and (4) the period of the pendulum (the time it takes for the pendulum to swing through one complete oscillation).
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
1. Length of the pendulum 2. acceleration due to gravity at that place
The weight of the bob will determine how long the pendulum swings before coming to rest in the absence of applied forces. The period, or time of 1 oscillation, is determined only by the length of the pendulum.
The period is 1 second.
Suppose that a pendulum has a period of 1.5 seconds. How long does it take to make a complete back and forth vibration? Is this 1.5 second period pendulum longer or shorter in length than a 1 second period pendulum?
1/4 Hertz or 1.4 per second.
If the length of the second pendulum of the earth is about 1 meter, the length of the second pendulum should be between 0.3 and 0.5 meters.
The physical parameters of a simple pendulum include (1) the length of the pendulum, (2) the mass of the pendulum bob, (3) the angular displacement through which the pendulum swings, and (4) the period of the pendulum (the time it takes for the pendulum to swing through one complete oscillation).
the time period of a pendulum is proportional to the square root of length.if the length of the pendulum is increased the time period of the pendulum also gets increased. we know the formula for the time period , from there we can prove that the time period of a pendulum is directly proportional to the effective length of the pendulum. T=2 pi (l\g)^1\2 or, T isproportionalto (l/g)^1/2 or, T is proportional to square root of the effective length.
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
Period of a pendulum (T) in Seconds is: T = 2 * PI * (L/g)1/2 L = Length of Pendulum in Meters g = Acceleration due to gravity = 9.81 m/s2 PI = 3.14 The period is independent of the mass or travel (angle) of the pendulum. The frequency (f) of a pendulum in Hertz is the inverse of the Period. f = 1/T
1. Length of the pendulum 2. acceleration due to gravity at that place
T=1/f .5=1/f f=2
T=1/2l
The weight of the bob will determine how long the pendulum swings before coming to rest in the absence of applied forces. The period, or time of 1 oscillation, is determined only by the length of the pendulum.