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Q: If a regular polygon has exterior angles that measure approximately 17.14º each how many sides does the polygon have?

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The largest exterior angle measure is 120o. It is the exterior measure of an equilateral triangle (which is a regular polygon).

A regular polygon will have 360 sides with exterior angles of 181 degrees.

A regular 10 polygon

56

360/number of sides

73.2

360/number of sides = exterior angle

7 It is not possible for a regular polygon to have exterior angles of 180 degrees or less in plane geometry

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The sum of the exterior angles of a polygon = 360360 / 36 = 10 degrees

If it's a regular polygon then each exterior angle measures 36 degrees

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.

5 sides and it is a regular pentagon

Exterior angles for n sides = 360/n = 17.14, n = 360/17.14 = 21 sides

The measure of 1 exterior angle of a regular 8-sided polygon is equivalent to 45 degrees. Hope I helped! :)

For any polygon, regular or otherwise, the sum of exterior angles is always 3600.

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60 degrees

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Providing that it is a regular polygon then each exterior angle will measure 12 degrees

Providing that it is a regular 12 sided polygon then each exterior angle measures 30 degrees

The sum of a regular polygon's exterior angles is 360. 360 divided by 3 is 120.

Exterior angle of ANY regular n-sided polygon is 360/n degrees...