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It is not possible for a regular polygon to have exterior angles of 180 degrees or less in plane geometry

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Q: Each exterior angle of a regular polygon is approximately 51.43 How many sides does the polygon have?

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360/number of sides = exterior angle

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.

180-interior angle = exterior angle If it's a regular polygon then: 360/number of sides = exterior angle

A regular polygon that has an exterior angle of 60 degrees = 360/60 = 6 sides and it is an hexagon

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With a regular polygon: 360/exterior angle = number of sides

The largest exterior angle measure is 120o. It is the exterior measure of an equilateral triangle (which is a regular polygon).

360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360

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Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)

Each exterior angle of a regular polygon with n sides is 360/n degrees. Each interior angle of a regular polygon is 180 - Exterior angle. A direct formula for the interior angle is 180*(n-2)/n degrees.

360/number of sides = exterior angle

If each exterior angle is 9 degrees then it is a regular 40 sided polygon.

360/number of sides = exterior angle

360/number of sides = exterior angle

Each exterior angle is 15 degrees

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.