Magnituide of acceleration = (change in speed) divided by (time for the change)
= (final speed - initial speed) divided by (time for the change)
= 2/20 = 0.1 meter per second2
Note that this is the magnitude of the acceleration, obtained by working with the speeds.
We don't know the initial or final velocities, because there's no information regarding directions.
Similarly, we only know the magnitude of the acceleration, not its direction.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
Kilometers/hour2. Note that for this kind of calculation, it is much more common to measure distances in meters, time in seconds, velocity in meters/second, and acceleration in meters/second2.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Average acceleration = (change in speed) divided by (time for the change)= (80) / (20) = 4 meters per second2
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
velocity = acceleration x time 27 = acceleration x 10 acceleration = 2.7 m/sec/sec
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
Kilometers/hour2. Note that for this kind of calculation, it is much more common to measure distances in meters, time in seconds, velocity in meters/second, and acceleration in meters/second2.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
The differences are that acceleration refers to the rate of change in velocity of an object while velocity is the rate of displacement of an object, and acceleration is measured in meters per squared seconds while velocity is measured in meters per second. On the other hand, they both use time as a component and they are both vectors in nature.
The acceleration of gravity is 9.8 meters per second2 .In 3 seconds, gravity increases the falling speed by (9.8 x 3) = 29.4 meters per second.This particular ball already had a downward speed of 6 m/s when the 3 seconds began,so at the end of the 3 seconds, its velocity is(6) + (9.8 x 3) = 35.4 meters per second downward
If air resistance is negligible, velocity increases at a rate of 9.8 meters / second every second, that is to say, the acceleration is 9.8 meters per second square.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)