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A weightlifter lifts 140 kg to a height of 1.5 m in 10 seconds. What is the power used?
Power is calculated using the formula ( P = \frac{W}{t} ), where ( W ) is the work done and ( t ) is the time taken. The work done ( W ) is equal to the weight lifted (force due to gravity) multiplied by the height, ( W = mgh ). For a weightlifter lifting 140 kg to a height of 1.5 m, the work done is ( W = 140 , \text{kg} \times 9.81 , \text{m/s}^2 \times 1.5 , \text{m} = 2058.15 , \text{J} ). Thus, the power used is ( P = \frac{2058.15 , \text{J}}{10 , \text{s}} = 205.82 , \text{W} ).
What is the power of a bulb that uses 3 jolts every 10 seconds?
Power is calculated as energy consumed per unit time. If a bulb uses 3 joules of energy every 10 seconds, its power can be calculated using the formula: Power (in watts) = Energy (in joules) / Time (in seconds). Therefore, the power of the bulb is 3 joules / 10 seconds = 0.3 watts.
What is the power if 35N force 5 Meters and takes 19 seconds to push?
Power = (energy) / (time) = (35 x 5) / 19 = 175 newton-meters / 19 seconds = 9.2105 watts (rounded)
How many ms are in 6.7 seconds?
6.7 times 10 to the -3 power
During a winter storm an entire town lost power for 2.6 hours How many seconds is this?
2.6 hours = 2.6*60 minutes = 156 minutes = 156*60 seconds = 9360 seconds.
A weightlifter is able to lift 250 kg 2.00 m in 2.00 seconds What is his power output?
Power output can be calculated using the formula: Power = Work / Time. The work done in lifting the weight is equal to the gravitational force (weight) multiplied by the height lifted: Work = Force × Distance = (250 kg × 9.81 m/s²) × 2.00 m = 4905 J. Therefore, the power output is 4905 J / 2.00 s = 2452.5 W. So, the weightlifter's power output is approximately 2453 watts.
What makes a press a power press?
A power press is classified based on its tonnage capabilities, with high tonnage presses considered power presses. They are capable of producing high force to shape or form materials like metal sheets. Power presses also have built-in safety features and controls to handle the high forces involved.
A weightlifter lifts 140 kg to a height of 1.5 m in 10 seconds. What is the power used?
Power is calculated using the formula ( P = \frac{W}{t} ), where ( W ) is the work done and ( t ) is the time taken. The work done ( W ) is equal to the weight lifted (force due to gravity) multiplied by the height, ( W = mgh ). For a weightlifter lifting 140 kg to a height of 1.5 m, the work done is ( W = 140 , \text{kg} \times 9.81 , \text{m/s}^2 \times 1.5 , \text{m} = 2058.15 , \text{J} ). Thus, the power used is ( P = \frac{2058.15 , \text{J}}{10 , \text{s}} = 205.82 , \text{W} ).
What is the power expended when a barbell is lifted 2.2m in 2 seconds?
The power during the lift is (weight of the barbell in Newtons)/4.4 watts.Note:Power is not "expended". Energy is. Power is the rate at which energy is expended.
An elevator lifts five passengers 30 meters in 24 seconds the power is 15000 watts what is the total weight of the elevator and passengers?
12,000 N, since force is equal to weight in this situation
A weight lifter has lifted 150 kg to a height of 2 m. He now lowers it carefully to the floor in 5 seconds. How much power is used Remember the force of an object's weight mass and times gravity.?
The work done in lowering the weight is equal to the force of gravity (150 kg * 9.8 m/s^2) times the distance moved (2 m). This gives us the total work done. To calculate power, we divide this work by the time taken (5 seconds). This gives us the power used by the weight lifter in lowering the weight.
How much power does a weightlifter expend when lifting a 50-kg barbell a vertical distance of 1.2 m in a time interval of 1.5 s?
The work done by the weightlifter is calculated by ( W = F \cdot d ), where ( F ) is the force applied (equal to the weight of the barbell, which is 50 kg * 9.8 m/s^2) and ( d ) is the vertical distance (1.2 m). Thus, ( W = 50 kg * 9.8 m/s^2 * 1.2 m ). Power is then power is given by ( P = \frac{W}{t} ) where ( t = 1.5 s ). Substituting values, we get ( P = \frac{50 kg * 9.8 m/s^2 * 1.2 m}{1.5 s} ). Calculating this gives the power expended by the weightlifter.
What is the power of a machine that lifts a N object 4 in 6 seconds?
The power of the machine can be calculated using the formula Power = Work/Time. Given that Work = Force x Distance, and the force required to lift the object will be its weight (N), the power can be calculated using the force (weight of object) and the distance it is lifted in the given time frame.
What are the most effective volleyball weight training exercises to improve performance on the court?
The most effective volleyball weight training exercises to improve performance on the court include squats, lunges, deadlifts, and shoulder presses. These exercises help to build strength, power, and stability in the muscles used for jumping, hitting, and blocking in volleyball.
How much power is necessary to do 60 joules of work in 20 seconds?
The power required to do 60 joules of work in 20 seconds is determined by the formula: Power = Work / Time. Therefore, Power = 60 joules / 20 seconds = 3 watts. So, 3 watts of power is necessary to do 60 joules of work in 20 seconds.
Which power of a telescope might be expressed as 0.5 seconds or arc?
which power of a telescope might be expressed as "0.5 seconds of arc"?
What is the power of a bulb that uses 3 jolts every 10 seconds?
Power is calculated as energy consumed per unit time. If a bulb uses 3 joules of energy every 10 seconds, its power can be calculated using the formula: Power (in watts) = Energy (in joules) / Time (in seconds). Therefore, the power of the bulb is 3 joules / 10 seconds = 0.3 watts.
