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A weightlifter lifts 140 kg to a height of 1.5 m in 10 seconds. What is the power used?
Power is calculated using the formula ( P = \frac{W}{t} ), where ( W ) is the work done and ( t ) is the time taken. The work done ( W ) is equal to the weight lifted (force due to gravity) multiplied by the height, ( W = mgh ). For a weightlifter lifting 140 kg to a height of 1.5 m, the work done is ( W = 140 , \text{kg} \times 9.81 , \text{m/s}^2 \times 1.5 , \text{m} = 2058.15 , \text{J} ). Thus, the power used is ( P = \frac{2058.15 , \text{J}}{10 , \text{s}} = 205.82 , \text{W} ).
What is the power of a bulb that uses 3 jolts every 10 seconds?
Power is calculated as energy consumed per unit time. If a bulb uses 3 joules of energy every 10 seconds, its power can be calculated using the formula: Power (in watts) = Energy (in joules) / Time (in seconds). Therefore, the power of the bulb is 3 joules / 10 seconds = 0.3 watts.
How much power does it take to lift 30.0 N 10.0 m high in 5.00s?
To calculate the power required to lift a weight, you first determine the work done, which is the force multiplied by the distance: Work = Force × Distance = 30.0 N × 10.0 m = 300 J. Power is the work done over time: Power = Work / Time = 300 J / 5.00 s = 60 W. Therefore, it takes 60 watts of power to lift the 30.0 N weight 10.0 m high in 5.00 seconds.
What is the power of a CD player if it uses 60000 joules for 30 minutes?
To find the power of the CD player, we can use the formula for power, which is energy divided by time. Here, the energy used is 60,000 joules and the time is 30 minutes, which is 1,800 seconds (30 minutes × 60 seconds/minute). Therefore, power = 60,000 joules / 1,800 seconds = 33.33 watts. Thus, the power of the CD player is approximately 33.33 watts.
What is the power if 35N force 5 Meters and takes 19 seconds to push?
Power = (energy) / (time) = (35 x 5) / 19 = 175 newton-meters / 19 seconds = 9.2105 watts (rounded)
A weightlifter is able to lift 250 kg 2.00 m in 2.00 seconds What is his power output?
Power output can be calculated using the formula: Power = Work / Time. The work done in lifting the weight is equal to the gravitational force (weight) multiplied by the height lifted: Work = Force × Distance = (250 kg × 9.81 m/s²) × 2.00 m = 4905 J. Therefore, the power output is 4905 J / 2.00 s = 2452.5 W. So, the weightlifter's power output is approximately 2453 watts.
A weightlifter lifts 140 kg to a height of 1.5 m in 10 seconds. What is the power used?
Power is calculated using the formula ( P = \frac{W}{t} ), where ( W ) is the work done and ( t ) is the time taken. The work done ( W ) is equal to the weight lifted (force due to gravity) multiplied by the height, ( W = mgh ). For a weightlifter lifting 140 kg to a height of 1.5 m, the work done is ( W = 140 , \text{kg} \times 9.81 , \text{m/s}^2 \times 1.5 , \text{m} = 2058.15 , \text{J} ). Thus, the power used is ( P = \frac{2058.15 , \text{J}}{10 , \text{s}} = 205.82 , \text{W} ).
What makes a press a power press?
A power press is classified based on its tonnage capabilities, with high tonnage presses considered power presses. They are capable of producing high force to shape or form materials like metal sheets. Power presses also have built-in safety features and controls to handle the high forces involved.
What is the power expended when a barbell is lifted 2.2m in 2 seconds?
The power during the lift is (weight of the barbell in Newtons)/4.4 watts.Note:Power is not "expended". Energy is. Power is the rate at which energy is expended.
Why is power important for a weightlifter?
Power is crucial for a weightlifter because it combines strength and speed, enabling athletes to lift heavier weights more efficiently. High power output allows for quicker force application during lifts, which is essential for overcoming inertia and achieving optimal lift dynamics. Additionally, developing power can enhance overall performance, reduce the risk of injury, and improve explosiveness in movements, all of which are vital for success in competitive weightlifting.
An elevator lifts five passengers 30 meters in 24 seconds the power is 15000 watts what is the total weight of the elevator and passengers?
12,000 N, since force is equal to weight in this situation
How much power does a weightlifter expend when lifting a 50-kg barbell a vertical distance of 1.2 m in a time interval of 1.5 s?
The work done by the weightlifter is calculated by ( W = F \cdot d ), where ( F ) is the force applied (equal to the weight of the barbell, which is 50 kg * 9.8 m/s^2) and ( d ) is the vertical distance (1.2 m). Thus, ( W = 50 kg * 9.8 m/s^2 * 1.2 m ). Power is then power is given by ( P = \frac{W}{t} ) where ( t = 1.5 s ). Substituting values, we get ( P = \frac{50 kg * 9.8 m/s^2 * 1.2 m}{1.5 s} ). Calculating this gives the power expended by the weightlifter.
A weight lifter has lifted 150 kg to a height of 2 m. He now lowers it carefully to the floor in 5 seconds. How much power is used Remember the force of an object's weight mass and times gravity.?
The work done in lowering the weight is equal to the force of gravity (150 kg * 9.8 m/s^2) times the distance moved (2 m). This gives us the total work done. To calculate power, we divide this work by the time taken (5 seconds). This gives us the power used by the weight lifter in lowering the weight.
If the muscles of a weightlifter and a marathon runner were compared the marathon runner would have more what?
If the muscles of a weightlifter and a marathon runner were compared, the marathon runner would have more slow-twitch muscle fibers. These fibers are more efficient for endurance activities, as they are designed for prolonged, aerobic exercise, allowing the runner to sustain activity over long distances. In contrast, the weightlifter would have more fast-twitch fibers, which are suited for short bursts of strength and power.
What is the power of a machine that lifts a N object 4 in 6 seconds?
The power of the machine can be calculated using the formula Power = Work/Time. Given that Work = Force x Distance, and the force required to lift the object will be its weight (N), the power can be calculated using the force (weight of object) and the distance it is lifted in the given time frame.
What are the most effective volleyball weight training exercises to improve performance on the court?
The most effective volleyball weight training exercises to improve performance on the court include squats, lunges, deadlifts, and shoulder presses. These exercises help to build strength, power, and stability in the muscles used for jumping, hitting, and blocking in volleyball.
How much power is necessary to do 60 joules of work in 20 seconds?
The power required to do 60 joules of work in 20 seconds is determined by the formula: Power = Work / Time. Therefore, Power = 60 joules / 20 seconds = 3 watts. So, 3 watts of power is necessary to do 60 joules of work in 20 seconds.
