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Q: If a weightlifter presses 400n weight 0.5m over his head in 2 seconds what is the power of the weightlifter?

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The person's speed is 2 meters per second. The power required for him to accomplish that depends on his weight, on his efficiency of movement, on whether he's moving horizontally or vertically, etc., all of which the question neglects to specify.

Power = (energy) / (time) = (35 x 5) / 19 = 175 newton-meters / 19 seconds = 9.2105 watts (rounded)

6.7 times 10 to the -3 power

2.6 hours = 2.6*60 minutes = 156 minutes = 156*60 seconds = 9360 seconds.

Power is measured in watts, or joules per second. So in 90 seconds, 1200 joules of work is equal to 1200/90 watts or 13.3 watts.

Related questions

assume a = 10(m/s)/s power (w) = energy change/time 294 = (mass * 10 * 2)/10 then mass = (294*10 )/ (10*2) = 147kg

The power during the lift is (weight of the barbell in Newtons)/4.4 watts.Note:Power is not "expended". Energy is. Power is the rate at which energy is expended.

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12,000 N, since force is equal to weight in this situation

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That is called "power". Energy / time = powerIn SI units: Joules / seconds = WattsThat is called "power". Energy / time = powerIn SI units: Joules / seconds = WattsThat is called "power". Energy / time = powerIn SI units: Joules / seconds = WattsThat is called "power". Energy / time = powerIn SI units: Joules / seconds = Watts

You need to convert the time to seconds. Then, if you divide the work (in joules) by the time (in seconds), you will get the power in watts.