curve
If the Object is falling at a constant velocity the shape of the graph would be linear. If the object is falling at a changing velocity (Accelerating) the shape of the graph would be exponential- "J' Shape.
A distance time graph would show the distance traveled.
Displacement is distance from starting point. If the object is always travelling in the same direction then they are the same. If the object turns round, the distance would still be increasing, however the displacement would be decreasing at the same rate.
It would be a horizontal line, with a y-coordinate at the starting distance.
The answer will depend on whether the graph is a distance time graph or a speed time graph.The slope of a distance-time graph shows that speed of the object in the direction towards or away from the point of reference (usually the origin). It indicates absolutely nothing about its speed in any other direction. So, for example, an object could be rotating around the origin at the speed of light (the fastest possible) and the distance-time graph would show it being stationary bacause its distance from the origin is not changing!The slope of the speed-time graph indicated the acceleration of the object, again with the same qualification.
If the Object is falling at a constant velocity the shape of the graph would be linear. If the object is falling at a changing velocity (Accelerating) the shape of the graph would be exponential- "J' Shape.
A distance time graph would show the distance traveled.
Displacement is distance from starting point. If the object is always travelling in the same direction then they are the same. If the object turns round, the distance would still be increasing, however the displacement would be decreasing at the same rate.
Any curved line on a distance/time graph indicates the presence of accelerationthat's causing a change in the magnituide of the velocity. But if the object's speedis constant, and the acceleration is changing its direction only, then the line on theD-T graph would remain straight.In summary:Every curved line on a D-T graph reveals acceleration, but not every accelerationproduces a curved line on a D-T graph.
It would be a horizontal line, with a y-coordinate at the starting distance.
Straight line
At constant speed, the distance/time graph is a straight line, whose slope is equal to the speed.
The answer will depend on whether the graph is a distance time graph or a speed time graph.The slope of a distance-time graph shows that speed of the object in the direction towards or away from the point of reference (usually the origin). It indicates absolutely nothing about its speed in any other direction. So, for example, an object could be rotating around the origin at the speed of light (the fastest possible) and the distance-time graph would show it being stationary bacause its distance from the origin is not changing!The slope of the speed-time graph indicated the acceleration of the object, again with the same qualification.
On a accelerating body, Velocity and distance of an object are effected. For a graph plotted with Acceleration to Time, it directly gives the acceleration at any given instant. For a graph plotted with Velocity versus Time. The Slope at any instant would give the Acceleration. Or given the time frame, say A to B. Acceleration can be found out by subtracting velocity at A from velocity at B divided by the time frame A to B.
You would plot the distance on the y-axis and time on the x-axis
If the motion of the object in in n-dimensional space, then an n+1 dimensional graph, in which one axis shows the time and the remaining n dimensions are the coordinates of the object at that point in time. The wrong answer is a distance-time graph, since that does not show any radial motion. An object going round in a circle around the origin is at a constant distance and so a distance-time graph would show no motion which is certainly not true.
You cannot. A distance vs time graph only measures radial distance - that is, distance from the origin to the object. If the object is going around the origin along a circular path, the distance vs time graph will not show any change in distance.The [incorrect] answer that you are required to give is that the graph will be a horizontal line during that period. But as explained above, the horizontal graph only means the object has no movement towards or away from the origin, not that it has no movement.