x=0
x - 6x = 0-5x= 0x = 0/-5which equals x = 0
The derivative of x is not x. X is the same as x^1, so you use the power rule which decreases the power by one and brings the exponent down, giving 1x^0, which is equal to 1.
Simply put, No.
It equals 0
x=0
anything x 0 = 0
If ( x = 0 ) and ( y = 1 ), then ( xy = 0 \times 1 = 0 ). Therefore, the value of ( xy ) is 0.
maybe
x = 0
x squared -2x-3 equals 0 is the same as (x + 1)(x - 3) = 0
30 x 0
No because in this equation x = -6 -6--6 = 0