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Find the coordinate of X if XY equals 1 and the coordinate of Y is 0?
If Y = 0 then there is no value of X such that XY = 1.
Is xy equals 0 - x equals 0 or y equals 0 a biconditional statement?
maybe
If x equals -8 and xy equals 1 what does y equal?
So far you know that: x=-8 xy=1 so xy means x times y. If you split xy. y=1/x or y=1/-8 1/-8= -0.125 You can find out that this is correct with the formula xy=1 because -0.125 x -8 is 1.
X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
Prove that there do not exist real numbers x y and z such that x plus y plus z equals 0 and simultaneously 1 over x plus 1over y plus 1over z equals 0?
Suppose x + y + z = 0 then z = - x - y = -(x + y) . . . . . . (A) 1/x + 1/y + 1/z = 0 implies x, y and z are all non-zero: otherwise the reciprocals are undefined. then z ≠0 implies that x+y ≠0 (by (A)) so 1/x + 1/y + 1/[-(x+y)] = 0 (using (A)) so that 1/x + 1/y = 1/(x+y) ie (x + y)/xy = 1/(x + y) Now, since x+y ≠0, multiply both sides by x+y to give (x + y)2/xy = 1 or (x + y)2 = xy x2 + 2xy + y2 = xy x2 + xy + y2 = 0 so that x = [-y ± sqrt(y2 - 4y2)]/2 = [-y ± y*sqrt(-3)]/2 which is cannot be real if y is real.
