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Accelerating...or was accelerating.

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Q: If final velocity is greater than initial velocity an object is?
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How will the final velocity be greater then the initial velocity?

It doesn't necessarily mean that the final velocity is always greater than the initial, if the initial velocity was at rest or 0 m/s then any form of movement would be greater. In cases where the final is smaller is like running into a wall or a decrease in acceleration.


Why is it important to add the constant of integration immediately when the integration is performed?

When you do an integration, you are (implicitly or explicitly) recognizing that what you are integrating is a "rate of change". Your integration over a particular interval provides you with the answer to the question "what is the total change over this interval?". To get the total value of this quantity you must add the initial amount or value. That is represented by the constant of integration. When you integrate between specific limits and you are asking the question "how much is the total change" the initial value is not needed, and in fact does not appear when you insert the initial and final values of the variable over which you are integrating. So you must distinguish between finding the total change, or finding the final value. Re-reading this, I could have been a bit clearer. I'll give an example. Suppose something is accelerating at a constant acceleration designated by "a". Between the times t1 and t2 the velocity changes by a(t2-t1) which you get by integrating "a" and applying the limits t2 and t1. But the change in velocity is not the same as the velocity itself, which is equal to the initial velocity, "vo", plus the change in velocity a(t2-t1). This shows that the integral between limits just gives the accumulated change. but if you want the final VALUE, you have to add on the initial value. You might see a statement like "the integral of a with respect to time, when a is constant is vo + at ". You can check this by differentiating with respect to t, and you find the constant vo disappears. In summary, the integral evaluated by simply applying the limits gives the accumulated change, but to get the final value you have to add on the pre-existing value, and in this context the pre-existing value also carries the name of "constant of integration".


Continuously compounded interest- solve for interest rate?

r=ln((A/P)^1/t) Where: A is the Final amount P is the Initial amount t is the time passed r is the interest rate


How many solutions does an equation have when the variable adds out and the final sentence is false?

none


How do you find the derivative of a function that has been raised to a power greater than 1?

Let us say that f(x)=x^4A derivative is the opposite to an integral.If you were to integrate x^4, the first process is taking the power [which in this case is 4], multiplying it by any value before the x [which is 1], then subtracting 1 from the initial power [4]. This leaves 4x^3. The final step is taking the integral of what is 'inside' the power [which is (x)], and multiplying this to the entire answer, which results in 4x^3 x 1 = 4x^3If you were to derive (x)^4, you would just add 1 to the power [4] to become (x)^5 then put the value of the power as the denominator and the function as a numerator. This leaves [(x^5)/(5)]To assure that the derivative is correct, integrate it. (x^5) would become 5x^4. Since (x^5) is over (5), [(5x^4)/(5)] cancels the 5 on the numerator and denominator, thus leaving the original function of x^4

Related questions

If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?

Final velocity = Initial velocity +(acceleration * time)


If an object is accelerating what equation relates the acceleration of that object the initial velocity and the final velocity and time?

Vf = Vi + at Where Vf = final velocity Vi = initial velocity a = acceleration t = time


How will the final velocity be greater then the initial velocity?

It doesn't necessarily mean that the final velocity is always greater than the initial, if the initial velocity was at rest or 0 m/s then any form of movement would be greater. In cases where the final is smaller is like running into a wall or a decrease in acceleration.


How do you find final Velocity of an object?

The final velocity is (the initial velocity) plus (the acceleration multiplied by the time).


Formula in getting the acceleration of a moving object?

final velocity-initial velocity --------------------------------- time


How do you calculate an objects acceleration?

Acceleration is an object's change in velocity divided by its change in time. So: acceleration=(final velocity - initial velocity)/(final time - initial time)


When an object's final velocity is less than its initial velocity it has what kind of acceleration?

Negative acceleration.


Which is greater in positive acceleration initial or final velocity?

inital velocity (u) should be less


If the final velocity will be less than initial velocity the object is increasing speed or decreasing speed?

increasing speed


Can an object's acceleration be a negative number?

Yes it can be.When a body has its initial velocity greater than its final velocity, then the body can have negative acceleration since acc.=change in velocity/time


Can the effect of initial velocity on final velocity be predicted?

Well, (final velocity) = (initial velocity) + (acceleration x time)


The rate of the velocity of an object?

To calculate the velocity of an object you can use the formula v=d/t. v=velocity, d=distance, and t=time. You can also calculate velocity using a=change in v/change in t, v(final)=v(initial)+at, v(average)=v(final)+v(initial)/2, or v(final)^2=v(initial)^2+2ad, or p=mv.