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If license plates are 3letters followed by 3 numbers what is the probability of getting a plate with ROB?
Wiki User
∙ 14y ago
if repeating is allowed than 1/263= 1/17576, if repeating isn't allowed than it's 1/(26*25*24)=1/15600.
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∙ 14y ago
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What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has three numerals followed by two letters followed by three numerals?
This is one minus the probability of having no repeated letters. The probability of having no repeated numbers is 10/10 x 9/10 x 8/10 x 7/10 x 6/10 x 5/10 which equals 0.1512. The probability of having no repeated letters is 26/26 x 25/26 = 0.96153846153846153846153846153846 These multiplied together gives 0.14538461538461538461538461538462 1 minus this is 0.85461538461538461538461538461538 And so the probability of having a repeater letter or digit is roughly 0.855
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has two letters followed by three numerals followed by two letters?
I don't know how to get past this point but the probability of having a letter appear more than once is: 98176/456796 = 21.4% The likelihood of a digit appearing more than once is: 280/1000=28% If they need to be consecutive to count then the letters would be: 50726/456796 = 11.1% The numbers would be: 100/1000 = 10% I don't know how to combine these probabilities properly so I'll leave that to you to figure out or for someone else to improve on.
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has two numerals followed by two letters followed by four numerals?
There are ten digits and twenty-six letters, assuming unconstrained choice of both. The probability of getting a repetition in the first two digits is 10/100, since there are 10 repetitious combinations of two digits among the 100 pairs of digits possible.To calculate the probability of a repetition in the two letters, consider that there are 262 combinations, of which 26 X 25 do not contain repetitions. (There is free choice among 26 alternatives for the first letter, but only 25 choice for the following letter.) Therefore, the probability of a repetition within the two letters is (26)(25)/262 or 25/26.The chance of a repeated digit within the four digit bloc is (10)(9)(8)(7)/104) or 504/1000.If there is no repetition of a digit within either the two-digit bloc or the four-digit bloc, there is still a chance of repetition of a digit between the blocs. The chance of this is (8 X 7 X 6 x 5)/104 or 168/1000.To reach the final answer, it is advantageous to calculate first the probability of not getting the specified repetition and then subtract this number from one. The probability of not getting a repetition in the first bloc is 9/10, and the probability of not getting a repetition between the first and second blocs is 168/1000. Therefore, the probability of not getting a repetition within the first bloc or between the first and the second number blocs is the product of these two, or 1512/10,000. Further multiplications by the independent probabilities of no repetition within the two remaining blocs yields a value of about 2.88 X 10-4. Therefore, the probability of at least one of the repetitions specified is about 0.999712.
How many license plates can be made using two letters followed by two numbers followed by one letter?
1757600
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has one numeral follwed by seven letters followed by one numeral?
This is easiest to answer by working out the probability of not getting such a license plate and subtracting that from 1. There are 10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10 different possible license plates (since there are 10 digits: 0-9 and 26 letters: A-Z). To not have any repeated digits or letters, there are: 10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9 possible license plates (since the two digits must be different and the seven letters must all be different). Meaning the probability of getting one of these is: (10 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 9)/(10 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 10) = (25 x 3 x 23 x 11 x 21 x 9)/(26 x 13 x 13 x 13 x 13 x 13) = 3586275/9653618 ⇒ probability of getting at least one repeating digit or number is: 1 - 3586275/9653618 = 6067343/9653618≈ 0.629
What is the probability of getting a license plate with a repeated letter or digit if you live in a state that has a 3 letters followed by 2 numbers?
The number of license plates without a repeated letter or digit is 26x25x24x10x9 = 1 404 000. The number of license plates without any restriction is 26x26x26x10x10 = 1 757 600. Probability of a license plate without a repeated letter or digit = 1 404 000 /1 757 600 = 0.7988 Probability of a license plate with a repeated letter or digit = 1-0.7988 = 0.2022
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has three numerals followed by two letters followed by three numerals?
This is one minus the probability of having no repeated letters. The probability of having no repeated numbers is 10/10 x 9/10 x 8/10 x 7/10 x 6/10 x 5/10 which equals 0.1512. The probability of having no repeated letters is 26/26 x 25/26 = 0.96153846153846153846153846153846 These multiplied together gives 0.14538461538461538461538461538462 1 minus this is 0.85461538461538461538461538461538 And so the probability of having a repeater letter or digit is roughly 0.855
What is the probability of getting a job as a real estate agent?
If you have a valid RE license in your state, the probability is nearly 100%. That is because a broker hiring a new agent usually does not pay anything to the new agent until the agent completes a sale. Getting the job is not the same as getting a paycheck.
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has one numeral followed by two letters followed by six numerals?
This may not be quite as straightforward as it first seems. In the UK, which has a different letter-number combination, some letters are not used so as to avoid confusion for example O and 0, or I and 1. If that is the case, then the probability of a particular digit is not 1/10. Also, some letter combinations that spell offensive words are disallowed. The consequence is that not all 26 letters of the alphabet are used and those that are may not be used in the same proportion. This will probably not apply if there are only two letters.
What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has two letters followed by three numerals followed by two letters?
I don't know how to get past this point but the probability of having a letter appear more than once is: 98176/456796 = 21.4% The likelihood of a digit appearing more than once is: 280/1000=28% If they need to be consecutive to count then the letters would be: 50726/456796 = 11.1% The numbers would be: 100/1000 = 10% I don't know how to combine these probabilities properly so I'll leave that to you to figure out or for someone else to improve on.
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What is the probability of getting a license plate that has a repeated letter or digit if you live in a state that has two numerals followed by two letters followed by four numerals?
There are ten digits and twenty-six letters, assuming unconstrained choice of both. The probability of getting a repetition in the first two digits is 10/100, since there are 10 repetitious combinations of two digits among the 100 pairs of digits possible.To calculate the probability of a repetition in the two letters, consider that there are 262 combinations, of which 26 X 25 do not contain repetitions. (There is free choice among 26 alternatives for the first letter, but only 25 choice for the following letter.) Therefore, the probability of a repetition within the two letters is (26)(25)/262 or 25/26.The chance of a repeated digit within the four digit bloc is (10)(9)(8)(7)/104) or 504/1000.If there is no repetition of a digit within either the two-digit bloc or the four-digit bloc, there is still a chance of repetition of a digit between the blocs. The chance of this is (8 X 7 X 6 x 5)/104 or 168/1000.To reach the final answer, it is advantageous to calculate first the probability of not getting the specified repetition and then subtract this number from one. The probability of not getting a repetition in the first bloc is 9/10, and the probability of not getting a repetition between the first and second blocs is 168/1000. Therefore, the probability of not getting a repetition within the first bloc or between the first and the second number blocs is the product of these two, or 1512/10,000. Further multiplications by the independent probabilities of no repetition within the two remaining blocs yields a value of about 2.88 X 10-4. Therefore, the probability of at least one of the repetitions specified is about 0.999712.
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How many license plates can be made using two letters followed by two numbers followed by one letter?
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