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In which quardant are the terminal arms of the angle lie when sin thita is less then zero and cos thita is greater then zero?
The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant
How do you get the exact value of cos 135?
The magnitude of cos(135°) is the same as that of cos(45°) [cos(180° - 135°)], and the sign is negative because it is in the second quadrant of the Cartesian plane, so it's the reciprocal of the negative square root of two, about -0.707. The cosines of 2nd- and 3rd-quadrant angles are negative, and the sines of 3rd- and 4th-quadrant angles are negative.
What is the value of Cos 1?
The inverse cos of 1 is equal to o degrees. You can find this answer by knowing what angle measurement has cos equal to a value of 1.
What is cos in a math problem?
Its a ratio in a right angle triangle, cos angle = adjacent / hypotonuse.
What is tan theta in terms of sin theta in quadrant II?
tan = sin/cos Now cos2 = 1 - sin2 so cos = +/- sqrt(1 - sin2) In the second quadrant, cos is negative, so cos = - sqrt(1 - sin2) So that tan = sin/[-sqrt(1 - sin2)] or -sin/sqrt(1 - sin2)
What is a quadrantal angle?
A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
What is quadrantal angle?
A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.
How do you find the quadrant of A over 2 if cos A equals 1 over 10 and A is located in quadrant IV?
If A is in quadrant IV, then A/2 is in quadrant II. Yes, the fact than cos(A) is 0.1 means that A is in quadrant I or IV, but it really is not required in order to answer the question. It is superfluous.
In which quardant are the terminal arms of the angle lie when sin thita is less then zero and cos thita is greater then zero?
The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant
What is cos of a negative angle?
The cosine function is an even function which means that cos(-x) = cos(x). So, if cos of an angle is positive, then the cos of the negative of that angle is positive and if cos of an angle is negative, then the cos of the negative of that angle is negaitive.
What is cos 295?
Cos 295 fall s in the 4th quadrant where cosine is positive cos 295 = cos (360-295) = cos 65 = 0.4226
What is the value of Cos 1?
The inverse cos of 1 is equal to o degrees. You can find this answer by knowing what angle measurement has cos equal to a value of 1.
How do you get the exact value of cos 135?
The magnitude of cos(135°) is the same as that of cos(45°) [cos(180° - 135°)], and the sign is negative because it is in the second quadrant of the Cartesian plane, so it's the reciprocal of the negative square root of two, about -0.707. The cosines of 2nd- and 3rd-quadrant angles are negative, and the sines of 3rd- and 4th-quadrant angles are negative.
How would you find out the sin tan and cos of right angle triangle?
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
Value of cos 315?
cos 315 degrees is 4th quadrant same as cos (-45) degrees which is +0.7071
Find the exact value of the expression sinarctan-12?
Assume the angle u takes place in Quadrant IV. Let u = arctan(-12). Then, tan(u) = -12. By the Pythagorean identity, we obtain: sec(u) = √(1 + tan²(u)) = √(1 + (-12)²) = √145 Since secant is the inverse of cosine, we have: cos(u) = 1/√145 Therefore: sin(u) = -√(1 - cos²(u)) = -√(1 - 1/145) = -12/√145 Otherwise, if the angle takes place in Quadrant II, then sin(u) = 12/√145
What is the angle for cos equals 0.2874?
What is the angle with a cosine of 0.6946
