It is 0.9459
It is 0.1962
The probability of rolling a six is 1 out of 6, or 1/6. Now, perhaps your question is: If I roll a die 180 times, what is the probability of rolling a six at least once. This is the same as rolling a die 180 times and never once rolling a six. The probability is (5/6)180 which is 5.59 x 10-15.
Probability(at least 1 six) = 1 - probability(no sixes) = 1 - 5/6 x 5/6 x 5/6 = 1 - 125/216 = 91/216 ≈ 0.421 = 42.1%
If you mean rolling at least one three, the 1/3. If you mean exactly one three, then 5/18. and If you mean a sum of 3 for the two throws, the answer is 1/18
There is a 1/2 chance of rolling an odd number on either die, so 1/2 X 1/2 = 1/4. 1/4 is the probability that both die will have odd numbers, so 3/4 is the probability that at least one is even.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
The probability that 14 is rolled at least once is 1 - 5.5*10-32 which, for all intents and purposes, can be treated as 1.
It is 0.1962
The probability of rolling a six is 1 out of 6, or 1/6. Now, perhaps your question is: If I roll a die 180 times, what is the probability of rolling a six at least once. This is the same as rolling a die 180 times and never once rolling a six. The probability is (5/6)180 which is 5.59 x 10-15.
Probability(at least 1 six) = 1 - probability(no sixes) = 1 - 5/6 x 5/6 x 5/6 = 1 - 125/216 = 91/216 ≈ 0.421 = 42.1%
If you mean rolling at least one three, the 1/3. If you mean exactly one three, then 5/18. and If you mean a sum of 3 for the two throws, the answer is 1/18
It is 0.722... recurring.
There is a 1/2 chance of rolling an odd number on either die, so 1/2 X 1/2 = 1/4. 1/4 is the probability that both die will have odd numbers, so 3/4 is the probability that at least one is even.
The probability is 0.6187, approx.
The probability of rolling at least one 2 when rolling a die 12 times is about 0.8878. Simply raise the probability of not rolling a 2 (5 in 6, or about 0.8333) to the 12th power, getting about 0.1122, and subtract from 1.
one fourth
The probability of rolling at least one '1' with six dice is 66.5% [1-(5/6)^6]*100%