If we multiply the gcd and the LCM, we get the numbers.Call the numbers a and b.
So
16(LCM)=ab3584=ab
let's all the LCM, x
16x=a(3584/a)using the information above.x= 1/16(3584)or x=224
So the LCM is 224
we can just say the (gcd)LCM=ab=3584, so just divide 3584 by 16.
if the gcd and lcm are given and one of the numbers are also given,multiply the gcd and lcm and divide them by the given number
800
The greatest common denominator (GCD) refers to a denominator that is COMMON to two or more numbers. You have only one number in the question! The greatest denominator of any number is itself.
The number that can be divided into both 35 and 56 is the greatest common divisor (GCD) of the two numbers. To find the GCD, you can use the Euclidean algorithm, which involves dividing the larger number by the smaller number and then using the remainder as the new divisor. Repeating this process will eventually lead to a common divisor. In this case, the GCD of 35 and 56 is 7.
Divide the larger number by the smaller one and then replace the larger by the remainder. Repeat until a remainder is 0 or both numbers are 1. In the first case, the non-zero number is the GCD, in the other case, the numbers are coprme: GCD = 1. Thus GCD(85, 102) 102 = 1*85 + R = 17 so GCD(85, 17) 85 = 5*17 + R = 0 so GCD(0, 17) therefore 17. = GCD[85, (102-85)] = GCD(85, 17)
47 is a prime number and 35 is smaller that 47 so their gcd is 1. Therefore their lcm is the product 35 * 47 which is 1645
17,303
The largest number that can divide both 21 and 14 is their greatest common divisor (GCD). To find the GCD, we can list the factors of each number: the factors of 21 are 1, 3, 7, and 21, while the factors of 14 are 1, 2, 7, and 14. The largest common factor is 7, so the GCD of 21 and 14 is 7.
I think you mean either the GCD or the LCM? Not sure which since they are relatively prime, the LCM will the the product of the three numbers and the GCD is 1
Euclid's algorithm is a popular algorithm to compute the GCD of two numbers. Algorithm: Gcd(a,b) = Gcd(b, a mod b), where a>=b and Gcd(a,0) = a Say we want to find the GCD of 72 and 105. 105 mod 72 = 33, so GCD(72,105) = GCD(33,72) 72 mod 33 = 6, so GCD(33,72) = GCD(6,33) 33 mod 6 = 3 so GCD(6,33) = GCD(3,6) 6 mod 3 = 0 so GCD(3,6) = GCD(0,3) = 3. So the GCD of 72 and 105 is 3.
#include void main(){int n1,n2,n3,i,gcd,s;printf("enter number n1,n2,n3:-");scanf("%d %d %d",&n1,&n2,&n3);if(n1
To find a number that goes into both 36 and 13, we can look for their greatest common divisor (GCD). The GCD of 36 and 13 is 1, since 13 is a prime number and does not divide 36. Therefore, the only integer that goes into both 36 and 13 is 1.