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#1="a" #2="b" #3="c" (a+b+c)/3=V if a=Z and b=Y, Z/3+Y/3+c/3=V Therefore: c/3=V/(Z/3+Y/3) c=3*V/(Z/3+Y/3)

I've encountered that on my GRE review. The given are: A. ZY - V

B. Z/V - 3 - Y

C. Z/3 - V - Y

D. 3V- Z - Y

E. V- Z - Y

if the 3rd missing letter is X, then maybe (I just guessed, so I'm not sure):

z/3+y/3+x/3=V

x/3=V -z/3 -y/3

3(x/3)=(V -z/3-y/3)3 cancel all corresponding 3's and times 3 to V

x= 3V-z-y

the answer is D.

Q: If the average of three numbers is V If one of the numbers is Z and another is Y what is the remaining number?

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Average of the three is v so their sum is 3v. One is z, another y so the third is 3v - z - y

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Average of the three is v so their sum is 3v. One is z, another y so the third is 3v - z - y

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The total of the 6 numbers is 48 (6x8) Adding another number will take the total to 7. So with an average of 10, the total of the 7 numbers will be 70 (7x10) 70 - 48 = 22 which is our seventh number.

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arrange the numbers from least to greatest or greatest to least, then cross out the Numbers back and forth on both sides one you get one number that is your median. if two numbers are remaining simply find the mean (the average) by adding the two numbers and then dividing by two

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