0
If the divisor is 40 what is the least three digit dividend that would give remainder of 4?
Wiki User
∙ 6y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is 9 remainer 45?
9 remainder 45 is the result of a division by a divisor of at least 46 and a dividend (dependent on the divisor) of at least 459. The divisor is one of 46, 47, 48, ... with a corresponding dividend of 459, 468, 477, ...
What is the least no should be subtracted from 316548 to make the result divisible by 365?
316548÷365 give 867 quotient 93 remainder Dividend-remainder= divisor*quotient 316548-93=365*867 which is 316455 93 should be subracted.
What is the least number that should be subtracted from 832 to make it exactly divisible by 48?
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
What is the least dividend that could be divided by 42 and have a 2 digit quotient?
420
What least no should be subtracted from 316548 make he result exactly divisible by 375?
316548/375 =844 quotient,48 remainder Dividend- remainder=divisor *quotient 316548-48=375*844 which gives 316500. Compare both that is 316548 and 316500 difference is 48. 48 is to be subracted.
What is 9 remainer 45?
9 remainder 45 is the result of a division by a divisor of at least 46 and a dividend (dependent on the divisor) of at least 459. The divisor is one of 46, 47, 48, ... with a corresponding dividend of 459, 468, 477, ...
What is the least no should be subtracted from 316548 to make the result divisible by 365?
316548÷365 give 867 quotient 93 remainder Dividend-remainder= divisor*quotient 316548-93=365*867 which is 316455 93 should be subracted.
What is the least number that should be subtracted from 832 to make it exactly divisible by 48?
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
What is a Java program that finds the greatest common factor of two integers?
The easiest way to find the greatest common denominator of two integers with a computer program is to use the Euclidean algorithm. Of the most popular methods of finding the GCD of two numbers, the Euclidean algorithm does it with the least amount of work and requires the least amount of code.In order to understand the Euclidean algorithm, you'll need to know a few division terms:The dividend is the number to be divided.The divisor is the number being divided by.The quotient is the number of times the divisor divides into the dividend.The remainder is the amount "left over" when the divisor cannot go into the dividend an integral number of times.18A divided by 12B gives a quotient of 1C and a remainder of 6D. A is the dividend, B is the divisor, C is the quotient, and D is the remainder.The Euclidean algorithm works like this:Check if either of the two integers is 0. If so, there is no solution (Ø), as a number cannot share a GCD with zero. Besides, division by zero is a big no-no.Check if either of the two integers is 1. If so, 1 is the GCD.Divide the larger of the two integers by the smaller.Divide the divisor of the previous division operation by the remainder of the previous operation.Repeat step four until the remainder equals zero. When the remainder equals zero, the divisor of the last operation is the GCD.If you still don't get it, try looking at the Euclidean algorithm in action:Find the GCD of 84 and 18.Check to see if either 84 or 18 is equal to 0. Nope. Continue on...Check to see if either 84 or 18 is equal to 1. Nope. Continue on...Since 84 is larger than 18, divide 84 by 18. Quotient is 4, remainder is 12.Take the divisor of the last operation (18) and divide it by the remainder of the last operation (12). Quotient is 1, remainder is 6.Take the divisor of the last operation (12) and divide it by the remainder of the last operation (6). Quotient is 2, remainder is 0.When the remainder is 0, the divisor of the last operation is the GCD. So the GCD in this case is 6.You should now have a good grasp of how the Euclidean algorithm works. Now we need to turn it into code. We'll need three variables, all of them integers:int divisor, dividend, remainder;The purpose of the variables is self-explanatory. Next, we need to make a few decisions. We need to decide if the dividend or the divisor is 0. If that test is passed, then we need to decide if the dividend or the divisor is 1. If that test is passed, then we need make sure that dividend is larger than divisor.if(dividend 1) {printf("The GCD is 1.\n");}// Make sure the dividend is greater than the divisor.if(divisor > dividend) {remainder = dividend;dividend = divisor;divisor = remainder;}// Calculate the GCD.while(remainder != 0) {remainder = dividend % divisor;dividend = divisor;divisor = remainder;}// Display the answer to the user.printf("The GCD is %i.\n", dividend);}And the GCD lived happily ever after. The end.
What is the least dividend that could be divided by 42 and have a 2 digit quotient?
420
What least number should be subtracted from 9660 so that the remainder is exactly divisible by 76?
Dividend-remainder=divisor *quotient 9660/76 gives 127 quotient and 8 remainder 9660-8=76*127 9652 so 8 must be subracted from 9660 ans is 8
What lest number must be subtracted from 13801 to get a number exactely divisibel by 87?
what least number must be subtracted from 13081 to get a number exactly divisible by 87
Why even divided by odd equal even?
Odd numbers do NOT have a factor of 2. When an Even number is divided by an Odd number with no remainder, the prime factors of the divisor cancel out the prime factors of the dividend, but there will be no prime 2 to cancel the prime factor of 2 in the dividend leaving the the quotient to have a factor of 2, and so will be Even. --------------------------------------------------------- Alternatively, consider what happens when you multiply Odd and Even numbers: Odd × Odd = Odd Odd × Even = Even Even × Even = Even The result is Even ONLY if at least one of the numbers multiplied together is Even. Thus if you divide an Even number by an Odd number, the result must be Even. Also consider that Odd times Odd is Odd. Multiplication is the inverse of division, so if you have: dividend ÷ divisor = quotient then dividend = quotient × divisor Now, if the divisor is Odd and the quotient is Odd, the the Dividend MUST be Odd (since Odd × Odd = Odd). Thus if the Dividend is Even and the Divisor is Odd, then the Quotient must be Even.
What least no should be subtracted from 316548 make he result exactly divisible by 375?
316548/375 =844 quotient,48 remainder Dividend- remainder=divisor *quotient 316548-48=375*844 which gives 316500. Compare both that is 316548 and 316500 difference is 48. 48 is to be subracted.
What is the least four digit number divided by 20 with a remainder of 5?
1005
What is the least common divisor of 10 and 45?
The divisor of a number is a number which divides into that number. The least divisor of any number 1, so the least common divisor of 10 and 45 is also 1. Perhaps you meant "Least Common Multiple" (the smallest positive number which 10 and 45 divide without remainder) in which case LCM(10, 45) = 90 Or you meant "Highest Common Factor" (the largest positive number which divides into both 10 and 45 without remainder) in which case HCF(10, 45) = 5.
If a three-digit number is divided by 5 or by 6 the remainder is 1 in each case what is the least such three-digit number?
121
