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Q: What least number should be subtracted from 9660 so that the remainder is exactly divisible by 76?

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3214195

what least number must be subtracted from 13081 to get a number exactly divisible by 87

The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.

13801-55 = 13746 and 13746/87 = 158

Yes, 48 is divisible by 8, exactly 6 times. Any number is divisible by 8, but not all are divisible evenly (that is, with no remainder). The only number that cannot be divided into another is 0 (zero).

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18 must be subtracted from 5694 to get a number exactly divisible by 43

3214195

what least number must be subtracted from 13081 to get a number exactly divisible by 87

96

16

Not exactly because it will have a remainder

If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7. or Divide 7 into it. If the answer has no remainder, the number is divisible by 7.

The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.

Yes, and the result is 60.5 (any rational number is divisible by 2) but I suspect the questioner might be thinking of "divisible by 2 with no remainder". On that path you start out by finding 60, with remainder 1. Sometimes the question is put as "is it Exactly divisible by 2?". Again, technically any rational number is "exactly" divisible by 2, but the word "exactly" has commonly come to imply "without remainder". So be careful.

13801-55 = 13746 and 13746/87 = 158

The fat that it is divisible means that the remainder must be zero.

Not exactly because it will have a remainder Not by a whole number of times 83594/3=27864.66666666667

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