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If the half-life of fluorine-18 is 110 minutes. approximately what percentage of a sample will remain after 200 minutes?
Wiki User
∙ 14y ago
Roughly, 200 minutes is twice 110 minutes, so about 1/4 (1/2 squared) of the original will remain. For a more accurate calculation, calculate (1/2)200/110.
Wiki User
∙ 14y ago
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