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If the interior of a polygon is 1080 degrees how many sides does it have?
Wiki User
∙ 13y ago
the sum of the angles in a polygon = the number of sides n less 2 x 180, or (n-2)*180. so the answer to the Q is as follows
1080 = 180*(n-2); n = 2+ (1080/180)
Wiki User
∙ 13y ago
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What would the name for a polygon that measures 1080 degrees?
An octagon has interior angles of 1080 degrees.
What is the sum of the internal angles of a polygon with eight sides?
The 8 interior angles add up to 1080 degrees
What is the sum of the interior angles of a regular octagon?
The interior angles of any polygon add up to the number of sides - 2, times 180 degrees. For an octagon this is 180 x 6 with is 1080 degrees, thus: The sum of the interior angles of a regular octagon is 1080 degrees
How do you find the measure of each angle of a regular polygon with 8 sides?
Total angles: (8-2)*180 = 1080 degrees Each interior angle: 1080/8 = 135 degrees
What is the sum of the inerior angles of a polygon with 8 sides?
The interior angles of an 8 sided octagon add up to 1080 degrees
What polygon has interior angles that measure 1080 degrees?
The interior angles of an octagon add up to 1080 degrees
What would the name for a polygon that measures 1080 degrees?
An octagon has interior angles of 1080 degrees.
What is the sum of the internal angles of a polygon with eight sides?
The 8 interior angles add up to 1080 degrees
How many interior and exterior degrees does a T shaped polygon have?
Because it has eight sides it is an octagon so:- Exterior angles: 360 degrees Interior angles: 1080 degrees
If the sum of the interior angles of a polygon is 1080 how many sides does the polygon have?
8
What polygon is the interior angle of 1080 degrees?
The interior angles of an 8 sided octagon add up to 1080 degrees
If the sum of interior angle measures of a polygon is 1080 how many sides does the polygon have?
8
How many sides does a polygon with an interior angle measure of 1080 have?
If the polygon has n sides, the sum of its interior angles is 180*(n-2) = 1080 So n-2 = 1080/180 = 6 And therefore n = 8
What is the sum of the interior angles of a regular octagon?
The interior angles of any polygon add up to the number of sides - 2, times 180 degrees. For an octagon this is 180 x 6 with is 1080 degrees, thus: The sum of the interior angles of a regular octagon is 1080 degrees
How do you find the measure of each angle of a regular polygon with 8 sides?
Total angles: (8-2)*180 = 1080 degrees Each interior angle: 1080/8 = 135 degrees
If the number of sides of a polygon is increased by five by how much would the sum of the interior angles of the polygon increase?
By 900 degrees as for example a triangle has 3 sides that add up to 180 degrees then if 5 sides are added to it then it then is an 8 sided octagon with interior angles that add up to 1080 degrees
What are the number of sides in a polygon if the sum of interior angles is 1080 degress?
8 sides
