That is correct (unless the number IS 0)
This is because any number that ends in 0 can be divided by 10 (e.g. 10, 20,100, 1864650). Since 10 is a factor of your number, and 2 and 5 are factors of 10, this means that 2, 5 and 10 must all be factors of your number.
There may of course be other factors too like 30 has 3 as a factor also.
Hope this helps
Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 117 is a 7 which is NOT a 0, so 117 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
No. 26 is not evenly divisible by ten. ----------------------------------------------------------------- All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 26 is a 6 which is NOT a 0, so 26 is NOT divisible by 10.
Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.
If two of the prime factors are 2 and 5, the last digit of the number will be zero.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 926 is a 6 which is NOT a 0, so 936 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 117 is a 7 which is NOT a 0, so 117 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
No. 26 is not evenly divisible by ten. ----------------------------------------------------------------- All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 26 is a 6 which is NOT a 0, so 26 is NOT divisible by 10.
"Composite" means that the number has smaller factors; "prime" means that it doesn't. Look at the last digit. If the digit is 0, 2, 4, 6, or 8, the number is divisible by 2. If the last digit is 0 or 5, the number is divisible by 5. If it none of those, the number may still have additional factors; but checking for this last digit can often quickly give you an answer.
Yes - since the last digit is 0, we know that 32940 is divisible by 10.
No. A whole number is (evenly) divisible by 10 only if its last digit is ' 0 '.
It is 0.
Yes, 78 is divisible by 10. When you divide 78 by 10, the result is 7 with a remainder of 8.