All multiples of 10 end in a zero
To be divisible by 10, the last digit must by a 0
The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
Multiples of 195.
No - 195/2 = 97.5
Yes. 195/3=65. 65x3=195.
Yes and it is 195/5 = 39
135. Every increase of 30 is also. Such as 165, 195, 225.
195 is composite because it is divisible by 5.
well, 1+9=10+5=15, which is divisible by 3, so it should be according to 3's divisabilaty rule.
Any of its multiples
195.
1, 3, 5, 13, 15, 39, 65, 195.
No, all multiples of 4 are even.
Yes. 390 divided by 2 is 195.