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If the perimeter is 150 and if the length is twice the width than what is the length and the width?
Wiki User
∙ 14y ago
If length is "l" and width is "w", then the equation can be written as:
2l+2w=150
because we know that in a quadrilateral, the perimeter is the length plus the length plus the width plus the width, or 2 times the length plus 2 times the width.
To simplify 2l+2w=150, we can divide each side by two:
2l+2w=150 (150 divided by 2= 75)
l+w =75
Now we know that the length plus the width is 75 units.
We know that the length is twice the length is twice the width, or:
l=2w
We can substitute this in for the length.
l+w =75
(2w)+w =75
3w=75
Now, we can divide each side by 3 to get the width:
3w=75 (75 divided by 3= 25)
w=25
The width=25 units
Now, we can figure out what the length is by putting in 25 for the width:
l+w=75
l+(25)=75
We can subtract each side by 25:
l+25=75 (75-25=50)
l=50
The length=50 units
We know this is correct because 50 (the length) is two times 25 (the width)
Wiki User
∙ 14y ago
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