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There seems to be a degree of difficulty about perimeter, which is just the measurement of the outline of the figure. It appears that your figure is a rectangle so the perimeter is merely twice (the sum of length and width, ie 150 units). If length exceeds width by 20 then length is 85 and width is 65.

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Q: Length is 20more than width and perimeter is 300?
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What is the width length and perimeter where the area equals 40 cm?

First of all, the area cannot be 40 cm since an area is 2-dimensional whereas the measure given is 1-dimensional. Next, the shape is not defined and so the width, length and perimeter are indeterminate. Even if you assume that the shape is a rectangle, the width, length and perimeter are indeterminate. On the basis that the length is greater than the width, all that you can say is that the length will be greater than or equal to sqrt(40) = 6.324555 (to 6 dp), the width will be 40 divided by that length and the perimeter will be twice their sum. Some examples: Length = 8, width = 5, perimeter = 26 Length = 10, width = 4, perimeter = 28 Length = 40, width = 1, perimeter = 82 Length = 4000, width = 0.01, perimeter = 8000.02 Length = 4,000,000, width = 0.00001, perimeter = 8,000,000.00002 and so on, without limit.


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