There seems to be a degree of difficulty about perimeter, which is just the measurement of the outline of the figure. It appears that your figure is a rectangle so the perimeter is merely twice (the sum of length and width, ie 150 units). If length exceeds width by 20 then length is 85 and width is 65.
First of all, the area cannot be 40 cm since an area is 2-dimensional whereas the measure given is 1-dimensional. Next, the shape is not defined and so the width, length and perimeter are indeterminate. Even if you assume that the shape is a rectangle, the width, length and perimeter are indeterminate. On the basis that the length is greater than the width, all that you can say is that the length will be greater than or equal to sqrt(40) = 6.324555 (to 6 dp), the width will be 40 divided by that length and the perimeter will be twice their sum. Some examples: Length = 8, width = 5, perimeter = 26 Length = 10, width = 4, perimeter = 28 Length = 40, width = 1, perimeter = 82 Length = 4000, width = 0.01, perimeter = 8000.02 Length = 4,000,000, width = 0.00001, perimeter = 8,000,000.00002 and so on, without limit.
12 meters
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
no one knows sorry!
10x2
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
length is 3 and width is 9
width=5 length=12
If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2
First of all, the area cannot be 40 cm since an area is 2-dimensional whereas the measure given is 1-dimensional. Next, the shape is not defined and so the width, length and perimeter are indeterminate. Even if you assume that the shape is a rectangle, the width, length and perimeter are indeterminate. On the basis that the length is greater than the width, all that you can say is that the length will be greater than or equal to sqrt(40) = 6.324555 (to 6 dp), the width will be 40 divided by that length and the perimeter will be twice their sum. Some examples: Length = 8, width = 5, perimeter = 26 Length = 10, width = 4, perimeter = 28 Length = 40, width = 1, perimeter = 82 Length = 4000, width = 0.01, perimeter = 8000.02 Length = 4,000,000, width = 0.00001, perimeter = 8,000,000.00002 and so on, without limit.
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
12 meters
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
Length = 20 m and width = 9 m
no one knows sorry!
10x2