Presumably the question is about finding the dimensions of a rectangle?
Let the length be 2x-3 and the width be x:
2(2x-3+x) = 36
4x-6+2x = 36
4x+2x = 36+6
6x = 42
x = 7
Therefore: length = 11 units and width = 7 units
80cm.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
l - 4 = 2w
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
You don't have enough information to find the exact length of the width, but the width has to be less then 7.5 if it smaller then the length.
4
80cm.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
length is 3 and width is 9
l - 4 = 2w
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
You don't have enough information to find the exact length of the width, but the width has to be less then 7.5 if it smaller then the length.
Let L be the length of the rectangle and W the width, then L = 2W - 3. The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6 But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4 The width of the rectangle is 4".
60 and 62
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar