l - 4 = 2w
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
The perimeter decreases by 4. Decreasing the length by 4 decreases the perimeter by 8. Increasing the width by 2 increases the perimeter by 4. -8+4=-4 For example: Area of a rectangle could be: 8 x 6 (8 being the length and 6 being the width). The perimeter is 8+8+6+6=28 If the length is decreased by 4 then it becomes 4 If the width is increased by 2 then it becomes 8. The perimeter becomes 4+4+8+8=24
Possibly. The perimeter of a rectangle is the distance around the outside of the rectangle. A rectangle has four sides with opposite sides being congruent. The formula for finding the perimeter is Side A + Side B + Side A + Side B-Devon
There is no such thing as a three sided rectangle. They have four sides. Length and width of a rectangle being THE SAME (having a 1:1 ratio) will provide the largest area possible. In other words, for a given perimeter, a square is the largest rectangle. If you mean a triangle (which has three sides), then all sides being equal will still yield the largest area.
Rectangles, being two-dimensional objects, do not have volume. Rectangular prisms, on the other hand, do. The equation for their volume is length*width*height, or lwh.
It depends on what side is being decreased All rectangles have perimeter 2l+2w where l is the length and w is the with if the length is decreased by 1 then the rectangle will have perimeter 2(l-1)+2w, similarly if the with is decreased by 1 then it will have perimeter 2l+2(w-1).
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
ok, i figured it out. the length of the triangle is 5, 4, 3. the four is 1/2 the length of one side of the rectangle. so the rectangle sides are 8, 8, 3, 3 (one three being one side of the rectangle as well)
The perimeter decreases by 4. Decreasing the length by 4 decreases the perimeter by 8. Increasing the width by 2 increases the perimeter by 4. -8+4=-4 For example: Area of a rectangle could be: 8 x 6 (8 being the length and 6 being the width). The perimeter is 8+8+6+6=28 If the length is decreased by 4 then it becomes 4 If the width is increased by 2 then it becomes 8. The perimeter becomes 4+4+8+8=24
Let h and w equal the dimensions of the rectangle and A equal its area 2h + 2w = 30 The perimeter of the rectangle is the sum of its sides, two widths and two heights h*w = A The formula for the area of a rectangle We have two equations but three unknown variables. Without more information about this rectangle, it is impossible to solve for the area from the perimeter alone unless this rectangle was specified as being a square (which gives us a third equation, b = h )
Possibly. The perimeter of a rectangle is the distance around the outside of the rectangle. A rectangle has four sides with opposite sides being congruent. The formula for finding the perimeter is Side A + Side B + Side A + Side B-Devon
The perimeter of a rectangle is twice the width added to twice the length -> 2(W) + 2(L) We are told that for this rectangle the perimeter = 2(W) + 110 So for this rectangle 2(L) = 110 Therefore L = 55 But this does not tell us enough to work out the width ..... if the width is 1 cm then the perimeter would be 2(1) + 110 and if the width is 300 cm then the perimeter would be 2(300) + 110 In each case the perimeter meets the requirement of being 110 cm more than twice the width.
It decreases. viz: perimeter of 5 x 5 square is 20 units, perimeter of 12.5 x 2 rectangle is 29 units...
There is no such thing as a three sided rectangle. They have four sides. Length and width of a rectangle being THE SAME (having a 1:1 ratio) will provide the largest area possible. In other words, for a given perimeter, a square is the largest rectangle. If you mean a triangle (which has three sides), then all sides being equal will still yield the largest area.
A = (1/2)Pa A being the area, P being the perimeter of the regular polygon, and the apothem length being a.
Rectangles, being two-dimensional objects, do not have volume. Rectangular prisms, on the other hand, do. The equation for their volume is length*width*height, or lwh.
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.