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If the speed of an object from 121m's to 98m's during a time interval of 12s what is the accelerations of the object?
Updated: 10/10/2023
Wiki User
∙ 14y agoBest Answer
Average acceleration is a net change in velocity over a corresponding change in time.
Your velocity went from 65 to 98 m/s - that's a positive change (gain) of 33 m/s.
the time interval was 12 s.
+ 33/12 m/s/s = + 2.75 m/s/s.
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∙ 14y agoThis answer is:
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If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
If the speed of an object changes from 121ms to 98ms during a time interval of 12 s what is the acceleration of the object?
We have this equation: Velocity after = Initial velocity + (acceleration * time) So, let's plug in the numbers into this equation. 98m/s = 121m/s + (acceleration * 12seconds) So, -23 = 12 seconds * acceleration dividing 12 from both sides, the acc. is -1.92m/s/s. (Yes, those are the UNITs of acceleration. And it's negative because the object slows down. )
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