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If the speed of an object changes from 121ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Wiki User
∙ 14y ago
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti).
a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
Wiki User
∙ 14y ago
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If the speed of an object changes from 121 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
-1.92 m/s2
Is the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
2.75 m/s
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
What are three components needed to find an object acceleration?
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
If the speed of an object changes from 121 minutes per second to 98 minutes per second during a time interval of 12 seconds what is the acceleration of the object?
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.
If the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
2.75 m/s
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
-1.92 m/s2
Is the velocity of an object changes from 65 ms to 98 ms during a time interval of 12 s what is the acceleration of the object?
2.75 m/s
If the speed of an object changes from 121 ms to 98 ms during a time interval of 12s what is the acceleration of the object?
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
If the speed of an object changes from 121 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?
B -1.92 m/s2
What are three components needed to find an object acceleration?
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
What changes as an object moves with a constant acceleration?
During constant acceleration, either the object's speed changes at a constant rate, or the direction of its motion changes at a constant rate, or both.
What is the formula to determine the acceleration of an object moving in a strait line?
Acceleration = (speed at the end of some time interval minus speed at the beginning of the interval)/(length of the time interval)
What is the rate at which an object velocity changes?
Acceleration
Is acceleration how quickly an object's velocity changes?
Yes, acceleration is the how the velocity changes. This also includes when an object turns
If the speed of an object changes from 121ms to 98ms during a time interval of 12 s what is the acceleration of the object?
We have this equation: Velocity after = Initial velocity + (acceleration * time) So, let's plug in the numbers into this equation. 98m/s = 121m/s + (acceleration * 12seconds) So, -23 = 12 seconds * acceleration dividing 12 from both sides, the acc. is -1.92m/s/s. (Yes, those are the UNITs of acceleration. And it's negative because the object slows down. )
Why at a constant speed if an object changes its direction it is considered to be acceleration?
Acceleration is a direction plus a speed. If either changes then the acceleration changes.
