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Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
No it is not. To check if a number is divisible by three - add all the digits of the number together (in this case they total 17). If the sum of the digits will divide by three then the original number will also. In this case 17 will not - so neither will the original number of 926. This rule also works for dividing a number by 9 !
No. To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not. For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9. Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.
You can add up the digits, 6+4+2=12 and if that number is divisible by three, so it the original number. So 12 is certainly divisible by 3 so that means 642 is also.
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Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
No it is not. To check if a number is divisible by three - add all the digits of the number together (in this case they total 17). If the sum of the digits will divide by three then the original number will also. In this case 17 will not - so neither will the original number of 926. This rule also works for dividing a number by 9 !
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!
In order for a number to be divisible by 4, it has to be even.As every multiple of 100 is divisible by 4, we only have to look at the rightmost two digits.If the number consisting of these digits is divisible by 4, then the original number is also divisible by 4.For example:353 is odd, therefore is not divisible by 4.1284 - We'll look at the rightmost digits giving us 84, which is divisible by 4, so 1284 is also divisible by 4.258 - The two rightmost digits give us 58, which is not divisible by 4. Hence 258 is also not divisible by 4.
No. To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not. For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9. Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.
Yes.To check divisibility by 4:if the last 2 digits are divisible by 4, then the original number is also divisible by 493032 - last 2 digits: 32 = 4 x 8 ⇒ 93032 is divisible by 4.(93032 ÷ 4 = 23258)
Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.
3 and 9
You would fill in the blank with the word sum, which means that you add each of the digits of the number. If that sum is divisible by three then the number is divisible by 3.
You can add up the digits, 6+4+2=12 and if that number is divisible by three, so it the original number. So 12 is certainly divisible by 3 so that means 642 is also.
To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.
Answer - How do you tell if a number is divisible by 3?you add all the digits in the number and see if that number can be divided by 3 Answer - A whole number is divisible by 3 if the sum of its digits is divisible by what?Three (3) Examples:* 27 -- 2+7=9 * 13452 -- 1+3+4+5+2=15 -- 1+5=6If the sum of the digits is divisible by 3, the number is also divisible by 3. Or just do the division.