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To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9.

As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3.

However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

Q: Is 32643 divisible by both 3 and 9?

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Both.

Neither, actually.

It is because 186426 = 3*62142 and 186426 = 9*20714.

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.

Because 3 and 9 are both divisible by 3, we can simplify this fraction into 1/3.

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why

Yes it is... If you add the digits of ANY number together - and the result can be divided exactly by 3 or 9 - then the original number will also divide by 3 or 9. Since the digits of this number add together to make 18 - then 32643 will also divide by 3 or 9.

9 is divisible by both 3 and 9

Every number is divisible by any non-zero number. Furthermore, 405 is evenly divisible by both 3 and 9.

Both.

Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.

Yes, both.

Yes to both.

3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.

Both no 380/9 = 42.2222 380/3 = 126.6666

Neither, actually.

no both are divisible by 3