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The sum of the three consecutive integers?
The sum of three consecutive integers is -72
What is the product of 15 consecutive integers whose average is7?
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
Write the sum of three consecutive integers using l where l the middle integer of the three?
The sum of three consecutive integers can be expressed using ( l ) as the middle integer. The three integers can be represented as ( (l-1) ), ( l ), and ( (l+1) ). Therefore, the sum is ( (l-1) + l + (l+1) = 3l ).
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
What are three consecutive odd integers that add up to 69?
21, 23, 25. Reasoning: Call the unknown middle member of the three consecutive integers m. Then m - 2 + m + m+2 =69; 3m = 69; m = 23.
What are the 4 consecutive odd integers where the sum of the middle two integers is equal to 24?
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
What is the equation for finding three consecutive integers whose sum is 176?
There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.
Find three consecutive integers such that three times the middle integer is one more than the sum of the first and third?
Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2
Find three positive consecutive odd integers such that the square of the middle integer increased by four times the largest integer is 173?
9,11,13
3 consecutive integeres whose sum is 93?
Middle integer must be a third of 93 so integers are 30, 31 and 32.
3 consecutive integers have the sum 153?
153/3 = 51The middle number is 51, so the numbers are...50, 51 and 52
The sum of ten consecutive integers is five what is the largest of these integers?
Well, well, well, look who's trying to do some math! If the sum of ten consecutive integers is five, then the middle number is 0. So, the largest integer would be 4. Keep crunching those numbers, honey!
